I am writing a program that analyzes a large directory text file line-by-line. In doing so, I am trying to extract different parts of the file and categorize them as 'Name', 'Address', etc. However, due to the format of the file, I am running into a problem. Some of the text i have is split into two lines, such as:
'123 ABCDEF ST
APT 456'
How can I make it so that even through line-by-line analysis, Python returns this as a single-line string in the form of
'123 ABCDEF ST APT 456'?
if you want to remove newlines:
"".join( my_string.splitlines())
" ".join( my_string.splitlines()) you'll get a space-separated string instead. But you will then get things like trailing spaces; at that point you probably want " ".join(line.strip() for line in mystring,splitlines())
Assuming you are using windows if you do a print of the file to your screen you will see
'123 ABCDEF ST\nAPT 456\n'
the \n represent the line breaks.
so there are a number of ways to get rid of the new lines in the file. One easy way is to split the string on the newline characters and then rejoin the items from the list that will be created when you do the split
myList = [item for item in myFile.split('\n')]
newString = ' '.join(myList)
To replace the newlines with a space:
address = '123 ABCDEF ST\nAPT 456\n'
address.replace("\n", " ")
import re
def mergeline(c, l):
if c: return c.rstrip() + " " + l
else: return l
def getline(fname):
qstart = re.compile(r'^\'[^\']*$')
qend = re.compile(r'.*\'$')
with open(fname) as f:
linecache, halfline = ("", False)
for line in f:
if not halfline: linecache = ""
linecache = mergeline(linecache, line)
if halfline: halfline = not re.match(qend, line)
else: halfline = re.match(qstart, line)
if not halfline:
yield linecache
if halfline:
yield linecache
for line in getline('input'):
print line.rstrip()
Name and Address so could be multiple fields per row, each potentially split on multiple lines. For example, this wouldn't be processed correctly 'name' 'address\nmore address'. But yeah very functional, and unlike most of the other answers, won't just return one giant single line with all newlines replaced by spaces.
'name'.Assuming you're iterating through your file with something like this:
with open('myfile.txt') as fh:
for line in fh:
# Code here
And also assuming strings in your text file are delimited with single quotes, I would do this:
while not line.endswith("'"):
line += next(fh)
That's a lot of assuming though.
i think i might have found a easy solution just put .replace('\n', " ") to whatever string u want to convert
Example u have
my_string = "hi i am an programmer\nand i like to code in python"
like anything and if u want to convert it u can just do
my_string.replace('\n', " ")
hope it helps
