How to pass an array from a php page to a js page? [duplicate]

Question

I have a php array of this type

[0] => Array
        (
            [id] => 22
            [lat] => 40.8434169
            [lng] => 11.409390199999962
        )

and I wish to pass it to a js file in body-onload.

I tried these ways:

1) <body onload="addMarkers(<?php print_r($myArray) ?>)">
2) <body onload="addMarkers(<?php echo json_encode($myArray) ?>)">

but without success

EDIT: I solved in this way

<script type="text/javascript">
    var myJsArray = <?php echo json_encode($myArray) ?>;
</script>

Also, learn how to debug JavaScript. Maybe the console gives you a clue why it "does not work". — Felix Kling
– Felix Kling, Commented Aug 23, 2013 at 18:22
While approach 2 should work, it doesn't make it right. Use AJAX to retrieve an array from a server page, it's cleaner and you decouple your php from your js files. — ILikeTacos
– ILikeTacos, Commented Aug 23, 2013 at 19:36

Jordi Jolink · Accepted Answer · 2013-08-23 18:17:15Z

0

I am not sure what your addMarkers() function does, but this might work:

<body onload="addMarkers(<?php echo implode(', ', $myArray); ?>)">

answered Aug 23, 2013 at 18:17

Jordi Jolink

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1 Comment

Felix Kling Over a year ago

That probably won't work since the first element of the array is an array itself. So echo implode(', ', $myArray); would result in the string "Array" or "Array, Array" if there are multiple.

Sergiu Paraschiv · Accepted Answer · 2013-08-23 18:17:59Z

0

<?php echo json_encode($myArray) ?>

Should work just fine. Open a development console and see what the JS interpreter has to say about the outputed code.

answered Aug 23, 2013 at 18:17

Sergiu Paraschiv

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Comments

Mithun Satheesh · Accepted Answer · 2013-08-23 18:20:28Z

0

first option you tried wont work in any case.But the second one is valid and passes a json object to your function

addMarkers(<?php echo json_encode($myArray) ?>)

If this doesnt work, error will be due to the reason that the addMarkers function doesnt expect an json object as its argumet. You can see this error description in your firebug console. Also you can check the function defintion to find out the expected argument.

answered Aug 23, 2013 at 18:20

Mithun Satheesh

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