Java fileOutputStream

Question

I have been looking around but could not find what I need. I am writing a simple code to save some strings into a .txt file.

I am using:

File archivo = new File(FileName);
fileOutputStream.write(toString().getBytes());
fileOutputStream.flush();

When I do this the .txt is succesfully created and save the info I need to save, BUT it save all in 1 single huge line. How I can save it in diffent lines?

example when I open the txt:

This is line 1This is line 2This is line 3This is line 4

I have add '\n' at the end of each string but it doesn't work.

toString() return a String: "This is line 1"; OS: Windows 7

What is the result of the method toString()? Can you show us the code of this method? — LaurentG
– LaurentG, Commented Sep 2, 2013 at 14:39
Check this out: docs.oracle.com/javase/7/docs/api/java/lang/… — blgt
– blgt, Commented Sep 2, 2013 at 14:46

Josh M · Accepted Answer · 2013-09-02 14:42:02Z

You could try doing something like this:

public void write(final File file, final List<String> lines) throws IOException{
    final BufferedWriter writer = new BufferedWriter(new FileWriter(file)); //new FileWriter(file, true) if you want to append the file (default is false)
    for(final String line : lines){
        writer.write(line);
        writer.newLine();
    }
    writer.flush();
    writer.close();
}

If you are using Java 8, feel free to try using lambdas:

public void write(final File file, final List<String> lines) throws IOException{
    final BufferedWriter writer = new BufferedWriter(new FileWriter(file)); //new FileWriter(file, true) if you want to append the file (default is false)
    lines.forEach(
            l -> {
                try{
                    writer.write(l);
                    writer.newLine();
                }catch(IOException ex){
                    ex.printStackTrace();
                }
            }
    );
    writer.flush();
    writer.close();
}

For usage, you could try this:

write(new File(fileName), Arrays.asList("This is line 1", "This is line 2", "This is line 3", "This is line 4"));

Parthi P · Accepted Answer · 2013-10-26 09:32:45Z

0

Use System.getProperty("line.separator"), which will return sequence used by operating system to separate lines in text files.

Try like this.

File archivo = new File(FileName);
fileOutputStream.write(toString().getBytes());
fileOutputStream.write(System.getProperty("line.separator").getBytes());
fileOutputStream.flush();

Ref : http://docs.oracle.com/javase/tutorial/essential/environment/sysprop.html

answered Oct 26, 2013 at 9:32

Parthi P

651 silver badge8 bronze badges

Comments

Huân Phan · Accepted Answer · 2021-05-05 04:04:50Z

-1

I think you should add '\n' to a StringBuilder before write.

StringBuilder sb = new StringBuilder();
sb.append("line 1" + "\n");
sb.append("line 2" + "\n");
sb.append("line 3" + "\n");

fileOutputStream.write(sb.toString().getBytes());

edited May 5, 2021 at 4:04

answered May 5, 2021 at 3:36

Huân Phan

842 silver badges4 bronze badges

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