Is possible to make inheritance in this xml using jaxb?

Question

I want to know if is possible to create a abstract class adress to using with job and home tags?

Like in this code

<person>
  <home>
    <adress>
      <street>marte</street>
      <number>200</number>
    </adress>
  </home>
  <job>
    <adress>
      <street>saint loius</street>
      <number>100</number>
    </adress>
  </job>
</person>

If is possible, can someome show me a example code...

@SotiriosDelimanolis i thougth it was good for the code, but i can be concrete class — Diego Macario
– Diego Macario, Commented Sep 5, 2013 at 14:42
@NarendraPathai @XmlSeeAlso({ AdressHome.class, AdressJob.class }) public abstract class Adress { @XmlElement(name = "street") private String street; @XmlElement(name = "number") private String number; //getter and setter } @XmlRootElement(name = "home") @XmlAccessorType(XmlAccessType.FIELD) public class AdressHome extends Adress { } @XmlRootElement(name = "job") @XmlAccessorType(XmlAccessType.FIELD) public class AdressJob extends Adress { } — Diego Macario
– Diego Macario, Commented Sep 5, 2013 at 14:48

bdoughan · Accepted Answer · 2013-09-05 15:01:43Z

1

This can be done by leveraging the @XmlElementRef annotation on a property in which the type is the common super class. Then annotate each subclass with the @XmlRootElement annotation.

http://blog.bdoughan.com/2010/11/jaxb-and-inheritance-using-substitution.html

answered Sep 5, 2013 at 15:01

bdoughan

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Diego Macario · Accepted Answer · 2013-09-06 01:35:49Z

0

My problem was in the interface class...

I didn´t put annotation to map the fields

answered Sep 6, 2013 at 1:35

Diego Macario

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