Act on a path passed as argument in a shell script

Question

I'm trying to print a list of the directories within a directory path i'm passing to a bash script. I know that

    ls -dn */

will print the list of only dirs within the current path, but i want to print the ones within the path i provided to the script.

i am guessing that you want to print only the path of the dir which you provide with your script . — Simmant
– Simmant, Commented Sep 6, 2013 at 14:23

anubhava · Accepted Answer · 2013-09-06 14:14:23Z

1

You can use ls with the variable also to list directories:

p="somepath"
ls -dn "$p"/*/

Or using find:

find "$p" -type d -maxdepth 1

answered Sep 6, 2013 at 14:14

anubhava

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3 Comments

-maxdepth 1 is not necessary

I added -maxdepth 1 to make sure to get directories from 1st level only, otherwise it will find directories from any level below given path.

mmm that useful, thank. by the way, i noticed that -maxdepth 1 should appear after "$p" and before -type..