String not matching in shell script

Question

I am trying to match two strings (IpAddress) as below. But it's not matching.

i=192.168.2.29
ipCheckInConfig="SG_1=192.168.2.24,192.168.2.29
> SG_2=192.168.2.20,192.168.2.23,192.168.2.31"

if echo "$i" | egrep -q "$ipCheckInConfig" ; then
    echo "Matched"
else
    echo "Not Matched"      
fi

Could someone please help?

The pattern is passed as a parameter, and the input is passed via standard input; you have them reversed. — user142162
– user142162, Commented Sep 18, 2013 at 15:01
What Tim said...and the pattern you're looking for is bigger than the input string you're giving to egrep, so of course it can't find the big string in the little one. You need to echo the long string and search for the short one. Or use the built-in regex operator if your shell is bash — the Unix and Shell tags don't make that a slam-dunk. — Jonathan Leffler
– Jonathan Leffler, Commented Sep 18, 2013 at 15:08

anubhava · Accepted Answer · 2013-09-18 15:05:15Z

4

You don't need to call egrep for that. Use bash's internal regex capabilities:

if [[ "$ipCheckInConfig" =~ $i ]]; then
    echo "Matched"
else
    echo "Not Matched"      
fi

answered Sep 18, 2013 at 15:05

anubhava

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4 Comments

Jonathan Leffler Over a year ago

Strictly, the question isn't tagged 'bash' and not all shells have the bash regex function.

anubhava Over a year ago

Oh sorry for overlooking that fact. user2531569: Are you using bash by any chance?

user2531569 Over a year ago

Thanks for ur reply. Yes i am using Bash only.

anubhava Over a year ago

If you're using BASH then my suggested answer should work fine.

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