24

I have a data.frame (or a matrix or any other tabular data structure object for that matter):

df = data.frame(field1 = c(1,1,1),field2 = c(2,2,2),field3 = c(3,3,3))

And I want to copy part of its columns - given in the vector below:

fields = c("field1","field2")

to a new data.table that already has 1 or more columns:

dt = data.table(fieldX = c("x","x","x"))

I'm looking for something more efficient (and elegant) than:

for(f in 1:length(fields))
{
dt[,fields[f]] = df[,fields[f]]
}
2
  • 1
    I don't understand what you're trying to do. Are you sure you mean data.table? Commented Sep 28, 2013 at 21:54
  • This is just a toy example of a bigger problem that I really have. I have a tabular data structure object (with many fields) from which I want to copy several fields to a data.table. Commented Sep 28, 2013 at 22:00

2 Answers 2

46

You can use cbind:

cbind(dt, df[fields])

However, the most efficient way is still probably going to be to use data.table's assign by reference:

dt[, (fields) := df[fields]]
Sign up to request clarification or add additional context in comments.

1 Comment

Interestingly, it seems you can add columns simultaneously. For eg., t = data.table(c1=1,c2=2); x = list(); x[1] <- 10; x[2] <- 100; invisible(foreach (i=1:2) %dopar% { input = x[[i]]; col = LETTERS[i]; t[ ,eval(col):= input] })
4

I think you want cbind

cbind(dt, df[, 1:2])
# fieldX field1 field2
# 1      x      1      2
# 2      x      1      2
# 3      x      1      2

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.