Find first index of a string after index

Question

I have a string: "www.google.com.sdg.jfh.sd"

I want to find the first ".s" string that is found after "sdg".

so I have the index of "sdg", by:

var start_index = str.indexOf("sdg");

now I need to find the first ".s" index that is found after "sdg"

any help appreciated!

What do you mean by "find the first .s index"? You want to find its position in the string? — matewka
– matewka, Commented Oct 3, 2013 at 15:17

Orkhan Alikhanov · Accepted Answer · 2019-08-03 01:34:12Z

153

There's a second parameter which controls the starting position of search:

String.prototype.indexOf(arg, startPosition);

So you can do

str.indexOf('s', start_index);

edited Aug 3, 2019 at 1:34

Orkhan Alikhanov

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answered Oct 3, 2013 at 15:16

lukas.pukenis

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Comments

matewka · Accepted Answer · 2015-08-12 21:30:08Z

26

This code might be helpful

var string = "www.google.com.sdg.jfh.sd",
  preString = "sdg",
  searchString = ".s",
  preIndex = string.indexOf(preString),
  searchIndex = preIndex + string.substring(preIndex).indexOf(searchString);

You can test it HERE

edited Aug 12, 2015 at 21:30

answered Oct 3, 2013 at 15:25

matewka

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2 Comments

Ionică Bizău Over a year ago

This concept is perfect when using regex for getting the index. indexOf(string), the next answer is obviously better, but in case of new RegExp(searchString, "g").exec(text).index, this is awesome. :-)

Aadhirai R Over a year ago

Fails when var string = "www.s.g.soogle.com.sdg.jfh.sd";

jasonslyvia · Accepted Answer · 2013-10-03 15:16:29Z

2

var str = "www.google.com.sdg.jfh.sd";
var search = "sdg";
var start_index = str.substring(str.indexOf(search) + search.length).indexOf(".s");

answered Oct 3, 2013 at 15:16

jasonslyvia

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