pass parameters to windows batch file multiple times

Question

I m having issues in passing parameters to a batch file.A parameter file will have n number of lines and i want to execute the bacth to read the first line,take that as a parameter in .bat and execute.Read the next line take it as second parameter execute again.Likewise it should execute n number of times if it finds n number of lines in text file.(For example if the text file have 100 lines the loop execution in .bat should continue for 100 times). I have script like,

@echo off

setlocal enabledelayedexpansion

set file1=D:\Batch\parm.txt

set /a cnt=0

for /f "tokens=*" %%a in (%file1%) do (

set %file1% =%%a

echo !%file1%!
)

FOR /F "tokens=1 delims=|" %%G IN (%file1%) DO set a1=%%G

FOR /F "tokens=2 delims=|" %%K IN (%file1%) DO set a2=%%K

FOR /F "tokens=3 delims=|" %%I IN (%file1%) DO set a3=%%I

echo parameter file found

echo reading parameters to pass through

echo (%a1%,%a2%,%a3%)>>D:\Batch\output.txt

goto break

:break

set /a cnt+=1
exit /b

my parameter file has input as

"India"|"Australia"|"Africa"

"I1"|"A1"|"A11"

"I2"|"A2"|"A12"

my output should be:

parameter file found

reading parameters to pass through

"India","Australia","Africa"

parameter file found

reading parameters to pass through

"I1","A1","A11"

parameter file found

reading parameters to pass through

"I2","A2","A12"

i m currently getting only last parameter as output.Please help me to correct the script.

dbenham · Accepted Answer · 2013-10-25 13:52:39Z

1

Your first FOR loop is crazy - it attempts to create a variable with a name that matches its value. I don't see how it serves any purpose.

Your logic is all wrong for each parameter. You read the entire file for the first parameter in a loop. When that loop is finished, you only have one parameter value for the last line found. You then do the same process for the 2nd and 3rd parameters. That can't work.

You should read all 3 parameters in a single loop.

@echo off
setlocal
set "file1=D:\Batch\parm.txt"
if exist "%file1%" (
  echo parameter file found
  echo reading parameters to pass through
  set /a cnt=0
  for /f "usebackq tokens=1-3 delims=|" %%A IN ("%file1%") do (
    echo (%%A,%%B,%%C^)
    set /a cnt+=1
  )
)>d:\batch\output.txt
echo cnt=%cnt%
exit /b

edited Oct 25, 2013 at 13:52

answered Oct 24, 2013 at 20:01

dbenham

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2 Comments

Gpg sam Over a year ago

Thanks for the help.Still i m unable to form loops.Output is something like parameter file found reading parameters to pass through "India","Australia","Africa" "I1","A1","A11" "I2","A2","A12" All parameters at same time.I want each parameter to execute one at a time along with echo statements.Count is showing as one.Would that be a issue for loop not repeating.Thanks once again

dbenham Over a year ago

@Gpgsam - There was a bug - the ) character had to be escaped in the ECHO statement. All fixed now. Count is now 3 as expected.

cure · Accepted Answer · 2013-10-24 14:44:34Z

0

@echo off

setlocal enabledelayedexpansion

set file1=D:\Batch\parm.txt

set /a cnt=0

for /f "tokens=*" %%a in (%file1%) do (

set %file1%=%%a

echo !%file1%!
)

FOR /F "tokens=1,2,3 delims=|" %%G IN (%file1%) DO set a1=%%a&set a2=%%b&set a3=%%c

echo parameter file found>>D:\Batch\output.txt

echo reading parameters to pass through>>D:\Batch\output.txt

echo (%a1%,%a2%,%a3%)>>D:\Batch\output.txt

goto break

:break

set /a cnt+=1
exit /b

answered Oct 24, 2013 at 14:44

cure

2,6781 gold badge19 silver badges26 bronze badges

1 Comment

Gpg sam Over a year ago

Thanks.Unable to form loops still.

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