redirect to url with parameters django python

Question

AoA, I am trying to redirect to view with parameters but unable to get the parameters

here is the code, it is working fine if I use (r'^search/$',... ) instead

url.py

url(r'^search/\?item=(?P<item_id>\d+)/$', 'contacts.views.search_Page', name='search_view'),

views.py

def search_Page(request,item_id):                   #GET Method
    return redirect('home_view')

it gives me no error, but django unable to find the page or view(404 page), why?

Using the URLconf defined in TestApp.urls, Django tried these URL patterns, in this order:

^$
^home/$ [name='home_view']
^logout/$
^save/$
^edit/$
^create/$
^account/$
^callback$ [name='callback']
^profile/$ [name='profile_view']
^search/\?item=(?P<item_id>\d+)$ [name='search_view']
^get/(?P<article_id>\d+)/$
^static\/(?P<path>.*)$
The current URL, search/item=4, didn't match any of these.

Paul Draper · Accepted Answer · 2013-11-05 20:57:44Z

3

Paths go in urls.py. Handling query parameters goes in the view.

url.py

url(r'^search/$', 'contacts.views.search_Page', name='search_view'),

views.py

def search_Page(request):
    address = request.GET['item'] # or GET.get('item', '') if the parameter might not exist
    print address

edited Nov 5, 2013 at 20:57

answered Nov 4, 2013 at 7:56

Paul Draper

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5 Comments

Saad Abdullah Over a year ago

then how can I pass parameter from the some previous view?

Saad Abdullah Over a year ago

i want to use query string from template search/?item=5 like this

Paul Draper Over a year ago

Then use request.GET.item in the template. Make sure you have django.core.context_processors.request.

Paul Draper Over a year ago

The URL that you redirect to must contain what ever query parameters want. You can do this from this view.

Saad Abdullah Over a year ago

first of all, thanks for your response. Its another headache to find the parameter, first I have to find the specific view I am calling, like the url.py is unable to find search view, if passed with parameter( look at the debug log above) but when I use the search view without any parameter, works fine

Konstantin Kovrizhnykh · Accepted Answer · 2013-11-04 08:18:09Z

0

Wrong regexp in urls.py. If you want to handle urls like search/?item=123/. Use this:

^search/\?item=(?P<item_id>\d+)/$

But better to use following with your view:

^search/(?P<item_id>\d+)/$

answered Nov 4, 2013 at 8:18

Konstantin Kovrizhnykh

1912 bronze badges

3 Comments

Konstantin Kovrizhnykh Over a year ago

But original url was search/?item=123. I mean with '?'

Saad Abdullah Over a year ago

it not working with any 127.0.0.1/search, nor with 127.0.0.1/search/?item=5

Konstantin Kovrizhnykh Over a year ago

It works with 127.0.0.1/search/?item=5/ If you want 127.0.0.1/search/?item=5 - then use ^search/\?item=(?P<item_id>\d+)$

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