I am trying to run the while loop until it equals to thirty.
<?php
$num1=0;
$num2=0;
$sum= $num1 + $num2;
while($sum=30){
$num1++;
$num2++;
echo "$sum is equal to 30";
}
?>
5 Answers
You need to change while($sum=30) to while($sum<30).
Then, the while loop will end after you reached 30. The echo then comes after the closing bracket.
Sp your working code will look like this:
while( $sum < 30 )
{
$num1++;
$num2++;
$sum = $num1 + $num2;
}
echo "sum is $sum (which is 30)";
4 Comments
bansi
your comparison is wrong
echo "$sum is 30"; will print 32 is 30
T3 H40
You are right. I'll fix this. Anyway he should check the result later on, too.
cypherabe
this works, but $sum will be 32 after the last loop cycle (if $num1 and $num2 start with 0) ;) - you enter the loop one last time at $sum == 30, increment both nums and calculate sum again
T3 H40
I know. In this case it works. But in reality you often work with variales that are more complex than here :)
You are calculating the sum outside the while loop, so inside the loop the $sum never changes. You have to calculate the sum inside the loop. also = is assignment operator. you must use comparison operator to compare.
$num1=0;
$num2=0;
$sum=0; //initilize you sum to 0
while($sum<30){ // loop while your sum is less than 30
$sum= $num1 + $num2; //calculate the sum
$num1++;
$num2++;
}
echo "$sum is equal to 30";
?>
Reference:Comparison Operators
3 Comments
alex472
This workds. But why did you change it to less than 30 ($sum<30) ?
bansi
The loop has to continue to calculate the sum till it reaches 30.
bansi
you can use
!= in your case, but if you start with $num1=1; or $num2=1; you may never hit sum of 30. so in that case < helps.use equality operator (==) not assignment operator (=)
Comments
This loop not ends. $sum ever is 0 !.
Comments
$num1=0;
$num2=0;
$sum= $num1 + $num2;
$x = 0;
while(!$x && $sum <=30){
$num1++;
$num2++;
$sum= $num1 + $num2;
if($sum ==30){
echo $sum." is equal to 30";
$x = 1;
}
}
Try this! Have a nice day !!
$sum= $num1 + $num2;should be inside thewhileloop or it is going to be a infinite loop.