Django Model store image file size

Question

I am using Django 1.6. I have a model for uploading image files that looks like this.

class Image(models.Model):
    id = models.AutoField(primary_key=True)
    name = models.CharField(max_length=255)
    url = models.ImageField(upload_to=get_image_path,
                             null=True,
                             blank=True,
                             height_field = 'height',
                             width_field = 'width',
                             verbose_name='Image')
    height = models.IntegerField(blank=True)
    width = models.IntegerField(blank=True)
    size = models.IntegerField(blank=True)
    format = models.CharField(max_length=50)
    caption = models.CharField(max_length=255)


    def clean(self):
        self.size = self.url.size

    class Meta:
        db_table = 'image'

As you can see, I am storing the size of the image when the clean() method is called. This works for what I want to do, but is this best practise? Is there a better way to automatically save the image's file size when saving?

The second part of my question is how can I get the content type as well?

Thanks, Mark

Community · Accepted Answer · 2017-05-23 12:21:37Z

1

Model.clean() should be used for validation - do not use it to update/save the data, but rather use it to correct any invalid data (or throw an exception/error message).

You may want to consider not even storing the size of the image in the database, given that you can access it from the ImageField - it eliminates the possibility of the data becoming inconsistent as it changes over time.

I believe this question/answer should address your second question.

edited May 23, 2017 at 12:21

CommunityBot

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answered Dec 5, 2013 at 17:51

Joseph Paetz

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Community · Accepted Answer · 2017-05-23 12:03:22Z

0

For the first question
Check out the Python Imaging Library PIL on this thread.

from PIL import Image
im=Image.open(filepath)
im.size # (width,height) tuple

For the second question
HttpRequest.META, more specifically HttpRequest.META.get('CONTENT_TYPE') from this thread

edited May 23, 2017 at 12:03

CommunityBot

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answered Dec 6, 2013 at 3:00

Daniel

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