ios validating text field input for some characters

Question

I am really new to ios development. while validating a text field i must ensure that it contains only 0-9 and special characters like * and #. Please help me out.

- (BOOL)validate:(NSString *)string{
    NSString *exp = @"^([0-9]+)?(\\.([0-9]{1,2})?)?$";
    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:exp options:NSRegularExpressionCaseInsensitive error:nil];
    NSUInteger numberOfMatches = [regex numberOfMatchesInString:string options:0 range:NSMakeRange(0, [string length])];
    if (numberOfMatches == 0)
        return NO;
    return YES;
}

You can set the keyboard type so it will contain only numbers and special characters. look here : developer.apple.com/library/ios/documentation/StringsTextFonts/… — giorashc
– giorashc, Commented Dec 12, 2013 at 9:31
but in ipad, the user has an option to change keyboard. it has an option of ABC in numeric keyboard. — user2932169
– user2932169, Commented Dec 12, 2013 at 9:34
This might helps you, stackoverflow.com/questions/2297102/… — aToz
– aToz, Commented Dec 12, 2013 at 9:35
@user2932169 Add code in body instead of comment. It should be more readable. — βhargavḯ
– βhargavḯ, Commented Dec 12, 2013 at 9:35

Bhumeshwer katre · Accepted Answer · 2013-12-12 09:31:34Z

1

Try this:

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string  {

    NSCharacterSet *cs = [[NSCharacterSet characterSetWithCharactersInString:@"0123456789*#"] invertedSet];

    NSString *filtered = [[string componentsSeparatedByCharactersInSet:cs] componentsJoinedByString:@""];

    return [string isEqualToString:filtered];
}

answered Dec 12, 2013 at 9:31

Bhumeshwer katre

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Comments

slecorne · Accepted Answer · 2013-12-12 09:46:11Z

0

You may try this:

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string  {

NSCharacterSet *numberAndSpecialCharsSet = [NSCharacterSet characterSetWithCharactersInString:@"0123456789*#"];

return ([string rangeOfCharacterFromSet:numberAndSpecialCharsSet].location==NSNotFound);

}

answered Dec 12, 2013 at 9:46

slecorne

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