I'm trying to figure out a regex pattern to find all occurrences in a string for this:
string = "List[5] List[6], List[10], List[100:] List[-2:] List[-2]"
re.findall("List[(.*?)]" , string)
# Expected output ['5', '6', '10', '100:', '-2:', '-2']
# Output: []
What would be a good regex pattern to get the numbers in between the indexes?
Square brackets are special characters in Regex's syntax. So, you need to escape them:
>>> import re
>>> string = "List[5] List[6], List[10], List[100:] List[-2:] List[-2]"
>>> re.findall("List\[(.*?)\]", string)
['5', '6', '10', '100:', '-2:', '-2']
>>>
Modifying iCodez answer a bit.
In [102]: import re
In [103]: string = "List[5] List[6], List[10], List[100:] List[-2:] List[-2]"
In [105]: re.findall("\[(.*?)\]", string)
Out[105]: ['5', '6', '10', '100:', '-2:', '-2']
Above will extract any character inside square bracket. If the string contains List[5] Add[3] output will be [5, 6]
In [115]: string = "List[4] tuple[3]"
In [116]: re.findall("\[(.*?)\]", string)
Out[116]: ['4', '3']
Above method will extract any characters inside square bracket.
