How to pass a bash variable into awk

Question

I have a variable that is created in bash, and want to use it within awk statement to create a file by concatenating it with a string for the filename.

awk -v value="${index}" 'BEGIN{}{print $9 >> "example_value.txt";}END{}'

How can I do this?

What I want is to change value with index to create multiple files such as example_1.txt, example_2.txt, etc. — yildizabdullah
– yildizabdullah, Commented Jan 5, 2014 at 13:11
This question is very common.. Strange that these type of things cannot be googled :) There must be at least 100 similar questions.. — Håkon Hægland
– Håkon Hægland, Commented Jan 5, 2014 at 13:41

Birei · Accepted Answer · 2014-01-05 13:06:51Z

4

You have to use it outside of the double quotes. awk concatenates it without any other character:

awk -v value="${index}" 'BEGIN{}{print $9 >> "example_" value ".txt";}END{}'

answered Jan 5, 2014 at 13:06

Birei

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Idriss Neumann · Accepted Answer · 2014-01-05 22:16:17Z

2

You could use -voption as in the examples previously posted.

Or you could just use something like :

awk 'BEGIN{}{print $9 >> "example_'"$index"'.txt";}END{}'

Moreover, you don't have to use {} around the variable index in this case.

answered Jan 5, 2014 at 22:16

Idriss Neumann

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