Returning the first index of a given array

Question

So I have a method called indexOf and by specifying a string in main, I can make the program print out the index of that string within the array. But how would I go about simply having a method that can print out the first index of an array, without me needing to specify a string, at all? If the index does not exist, I want it to return -1.

public static void main(String[] args)
{

    String[] v = new String[1];
    v[0] = "test";

    String s = "t";

    indexOf(v, s);
}

public static int indexOf(String[] v, String s)
{       
    int i = v[0].indexOf(s);
    System.out.println
        ("Index of the first string in the first array: " + i);

    return -1;                                      
    }
}

It's not clear what you're trying to do. The first index of an array will always be 0 (or undefined if the array has no elements). — David
– David, Commented Jan 27, 2014 at 15:46
Right now, I am going to get 0 printed out because String s = "t"; is the first string and it has the index 0. What I want, is for the program to actually print out "t" and basically recognize the first index and let me know what it is. — user3071133
– user3071133, Commented Jan 27, 2014 at 15:49
You never loop over the input array. You also never check the bounds of the input array. You do nothing with the return value of the function. — crush
– crush, Commented Jan 27, 2014 at 15:52
It's still really unclear what you're asking. Do you just want to print the first element in the array? Again, that element will always be at index 0, or undefined for an empty array. — David
– David, Commented Jan 27, 2014 at 15:52
@David I assume that he wants to use String.indexOf() on an array of String's, and return the first occurrence. What's unclear is how he plans on knowing to which element of the array the index belongs without returning either an array of int or some custom result type. — crush
– crush, Commented Jan 27, 2014 at 15:54

Community · Accepted Answer · 2017-05-23 10:25:55Z

0

Your question can be read two ways. If you want to be able to return just the first index of the array, then do the following:

if(v.length > 0)//check length
    return 0;//return first position
return -1;//return empty string meaning there wasnt a first position.

However, you may mean to ask to return the first case of a String s in the array v. Then in that case, do the following:

//assuming v and s are not null or do not contain null values
for(int i = 0; i < v.length; i++){//loop through the array v
    if(v[i].equals(s){//does the current value of v equal to the String s?
        return i;//found string!
    }
}
return -1;//didnt find the string

You seem new to java. I highly recommend reading these two sources:

Java: Array with loop

How do I compare strings in Java?

edited May 23, 2017 at 10:25

CommunityBot

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answered Jan 27, 2014 at 15:51

But I'm Not A Wrapper Class

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1 Comment

user3071133 Over a year ago

I was infact a bit confused but this answer helped me understand it. I was going for the first answer you gave. Essentially the index will always be 0 as long as the string exists, otherwise I wished to return -1.

Claudiu · Accepted Answer · 2014-01-27 15:46:36Z

0

The first index of an array is always 0. So you would just return v.length > 0 ? 0 : -1.

answered Jan 27, 2014 at 15:46

Claudiu

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