How to create this array in Ruby?

Question

I there a smarter way to define an array like this in Ruby?

array = [5, 15, 25, 35, 45, 55, 65, 75]

Thanks for any help.

Arup Rakshit · Accepted Answer · 2014-02-08 16:29:00Z

7

5.step(75, 10).to_a #=> [5, 15, 25, 35, 45, 55, 65, 75]

edited Feb 8, 2014 at 16:29

Arup Rakshit

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answered Feb 8, 2014 at 16:28

steenslag

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1 Comment

Arup Rakshit Over a year ago

You,, Ohh!!No.. every one in SO should :)

falsetru · Accepted Answer · 2014-02-08 16:23:40Z

6

Use Range#step:

Range.new(5, 75).step(10).to_a
# => [5, 15, 25, 35, 45, 55, 65, 75]

[*Range.new(5, 75).step(10)]
# => [5, 15, 25, 35, 45, 55, 65, 75]

[*(5..75).step(10)]  # (5..75) == Range.new(5, 75)
# => [5, 15, 25, 35, 45, 55, 65, 75]

answered Feb 8, 2014 at 16:23

falsetru

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Comments

berkes · Accepted Answer · 2014-02-08 16:25:57Z

4

Not sure if it is nicer, but one way would be:

a = 8.times.map {|i| i*10+5} #=> [5, 15, 25, 35, 45, 55, 65, 75]

The benefit of this method, is that the amount of items in the result (8) is explicit.

answered Feb 8, 2014 at 16:25

berkes

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Comments

Arup Rakshit · Accepted Answer · 2014-02-08 16:28:51Z

1

Here is one way :

>> Array.new(8) { |i| i*10 + 5 }
=> [5, 15, 25, 35, 45, 55, 65, 75]
>>

answered Feb 8, 2014 at 16:28

Arup Rakshit

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