PHP Simple form with IF Statement

Question

I am very new to PHP and currently working on developing my first form. With the below code sample I am trying to achieve two things.

If the fields for "name" or "email" are filled out in the form, then it will post "Your name is: "name" and "Your email is:"email".
If a field is not filled out, then it will display nothing at all.

I believe this needs to be done with an IF statement but I am having a hard time finding anything showing the protocol for if the field is empty. Any help would be greatly appreciated.

<form action="Test.php" method="post">
    Name: <input type="text" name="name"><br>
    E-mail: <input type="text" name="email"><br>
    <input type="submit">
</form>

<?php 

$name = $_POST["name"];
if($name="name") {
    echo "Your name is: $_POST["name"]" ;
} else {
    echo "";
}
?>
<br>

<?php 
$email = $_POST["email"];
if($email = "email") {
    echo "Your email is: $_POST["email"]" ;
} else {
    echo "";
}
?>

You have multiple PHP syntax errors... you canNOT use " quotes within a "-quoted string, nor are you allowed to use quoted array keys within "-quoted strings. Your if() tests are doing ASSIGNMENTS (=), not testing for equality (==). Basically, you need to study basic PHP syntax a bit more. — Marc B
– Marc B, Commented Feb 10, 2014 at 3:14
All you need is echo "Your name is: " . $name; etc. If you want to check if a name was entered, if(!empty($_POST['name'])) or if(isset... - Wait for the answers to roll in...vvvvv — Funk Forty Niner
– Funk Forty Niner, Commented Feb 10, 2014 at 3:14

Community · Accepted Answer · 2017-05-23 12:06:33Z

Your conditional statements are incorrect.

You're presently making an assignment using = with ($name="name") and ($email = "email") when you should be checking if something is "equal to" using ==.

Also, as Marc B stated in his comment: "you can NOT use " quotes within a " quoted string, nor are you allowed to use quoted array keys within " quoted strings..."

However, if you were to keep that strategy; i.e.: if($name=="name") then your form would only work if the words name and email were entered in the form's inputs.

There are a few ways to achieve this, checking if a field is (not) empty using if(!empty or if it is set if(isset.

In this case, I used if(!empty. Meaning, that if the fields are not empty, then echo the results afterwards.

This is a basic example: (There are other ways to achieve the same result)

<form action="Test.php" method="post">
Name: <input type="text" name="name"><br>
E-mail: <input type="text" name="email"><br>
<input type="submit">
</form>

<?php
$name = $_POST['name'];
if(!empty($_POST['name'])) {
    echo "Your name is: " . $name;
} else {
    echo "";
}
?>
<br>

<?php 
$email = $_POST['email'];
if(!empty($_POST['email'])) {
    echo "Your email is: " . $email;
} else {
    echo "";
}
?>

Silviu-Marian · Accepted Answer · 2014-02-10 03:15:24Z

0

This is all you need to write:

<html>
<body>

<form action="Test.php" method="post">
Name: <input type="text" name="name"><br>
E-mail: <input type="text" name="email"><br>
<input type="submit">
</form>

<?php

if(!empty($_POST['name']))
    echo "Your name is {$_POST['name']}. <br />";


if(!empty($_POST['email']))
    echo "Your email is {$_POST['email']}. <br />";

?>

</body>
</html>

P.S.: I really recommend reading an introductory book, at least to cover the basic functions. After that you can go directly to php.net and look for functions on-a-need basis.

answered Feb 10, 2014 at 3:15

Silviu-Marian

10.9k7 gold badges56 silver badges76 bronze badges

Comments

Community · Accepted Answer · 2023-11-20 22:45:59Z

0

You can use isset() to check if the variable is actually set. You could also use empty() to check that it exists and if there's a value stored. For example:

if (!empty($_POST['email')) {
    // do things
}

edited Nov 20, 2023 at 22:45

CommunityBot

11 silver badge

answered Feb 10, 2014 at 3:15

Anid Monsur

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