How to call many functions with requireJS

Question

I have two files: main.js and events.js.

In main.js i have defined some functions, which look's like this:

define(["jquery"], function() {

    var a =  {
       function_a: function(){
         some_actions;
       }
    }

    var b =  {
       function_b: function(){
         some_actions;
       }
    }

    return a, b;
});

and in events.js i have some calls for this functions:

require(['jquery','app/main'], function($, a){
    selector.on('click', function(){
        a.function_a();
    });
});

require(['jquery','app/main'], function($, b){
    selector.on('click', function(){
        b.function_b();
    });
});

Something is wrong because i can't call more than one of this functions, can anybody help?

return a, b; - this line doesn't work like you seem to think. — raina77ow
– raina77ow, Commented Feb 11, 2014 at 12:47

Piotr Stapp · Accepted Answer · 2014-02-11 13:35:08Z

2

Instead of return a,b which is invalid statement you need to return an object for example: return {'a':a, 'b':b}

Then in your code you can write:

require(['jquery','app/main'], function($, obj){
    selector.on('click', function(){
        obj.a.function_a();
        obj.b.function_b();
    });
});

You could use also array. Then return will be return [a,b] and in require function:

require(['jquery','app/main'], function($, obj){
    selector.on('click', function(){
        obj[0].function_a();
        obj[1].function_b();
    });
});

edited Feb 11, 2014 at 13:35

answered Feb 11, 2014 at 13:13

Piotr Stapp

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3 Comments

Lukas Over a year ago

ok, but this return should be var obj = { 'fn': a, 'fn': b }; return obj; ?

Piotr Stapp Over a year ago

you cannot have same id in JSON. You could use array. I will add update

raina77ow Over a year ago

A minor nitpick: return a,b is not a invalid statement per se - it's just meaningless, as only b value is returned. The fact that a is evaluated too is obviously of little use. ) But overall, very nice explanation, +1 from me.

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