I'm trying to remove a few lines matching some regex.
curl <url> | sed '/\(foo\|bar\|baz\)/d'
i don't want any of those lines to show that match foo, bar or baz
it stops on foo
if this is easier with awk, i'm ok with that.
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Do you mean "i don't want any of those lines to show that match foo, bar and baz"?potong– potong2014-02-20 09:50:52 +00:00Commented Feb 20, 2014 at 9:50
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your sed works fine in my env (CGYWIN)BMW– BMW2014-02-20 11:57:52 +00:00Commented Feb 20, 2014 at 11:57
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4 Answers
Or with egrep:
curl <url> | egrep -v "foo|bar|baz"
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Using awk
curl <url> | awk '!/foo|bar|baz/'
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try
curl <url> | sed '/foo\|bar\|baz/d'
also see many many close examples here: http://www.theunixschool.com/2012/06/sed-25-examples-to-delete-line-or.html
2 Comments
chovy
it actually works as expect. the docs say that it stops at first matching regex. i need to make it greedy, but /g did not work.
epeleg
you might find some of the things here stackoverflow.com/questions/5410757/… helpfull.
This might work for you (GNU sed):
sed '/foo/{/bar/{/baz/d}}' file
or:
sed '/foo/!b;/bar/!b;/baz/d' file
