Understanding OutputStream

Question

I am trying to understand outputStream first.I am reading from the book Java network programming 2ns edition by Merlin Hughes . There is a sample program in the book which i am trying to run and get its output but there is no output.i understand it but could not identify the problem .

here is the code

import java.io.*;

public class SimpleOut 
{
  public static void main(String[] args) throws IOException
  {
    for (int i=0; i<args.length; i++)
    {
        println (args[i]);
    }
  }

  public static void println(String msg) throws IOException
  {
    synchronized (System.out)
    {
        for (int i=0 ; i<msg.length(); i++)
            System.out.write(msg.charAt (i) & 0xff);

        System.out.write('\n');
    }
    System.out.flush();
  }
}

I understood the code.i didnt know about CLA ,i am noob if thats what you wanna hear NFE :( — user3085866
– user3085866, Commented Feb 22, 2014 at 17:33

Christian Tapia · Accepted Answer · 2014-02-22 17:28:36Z

2

It seems like you are not passing any command-line arguments while running the program.

When an application is launched, the runtime system passes the command-line arguments to the application's main method via an array of Strings.

Example: User should enter

java NameOfFile arg1 arg2 arg3

answered Feb 22, 2014 at 17:28

Christian Tapia

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4 Comments

user3085866 Over a year ago

Could you tell me what happens when synchronized (System.out) is executed.synchronized is used for synchronizing a thread ,how System.out is a thread?

Christian Tapia Over a year ago

Not an expert in that field. Try to do some research and if you can't figure it out, post it in StackOverflow as a different question. Feel free to accept this answer if it was useful and solved your problem: How does accepting an answer work

user3085866 Over a year ago

i am not allowed to ask more questions for 24 hours :(

Christian Tapia Over a year ago

Try to do some research an read this.

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