I am trying to run the example code at the following url. I compiled the program with "mpicc twoGroups.c" and tried to run it as "./a.out", but got the following message: Must specify MP_PROCS= 8. Terminating.
My question is how do you set MP_PROCS=8 ?
Group and Communication Routine examples at here https://computing.llnl.gov/tutorials/mpi/
#include "mpi.h"
#include <stdio.h>
#define NPROCS 8
main(int argc, char *argv[]) {
int rank, new_rank, sendbuf, recvbuf, numtasks,
ranks1[4]={0,1,2,3}, ranks2[4]={4,5,6,7};
MPI_Group orig_group, new_group;
MPI_Comm new_comm;
MPI_Init(&argc,&argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &numtasks);
if (numtasks != NPROCS) {
printf("Must specify MP_PROCS= %d. Terminating.\n",NPROCS);
MPI_Finalize();
exit(0);
}
sendbuf = rank;
/* Extract the original group handle */
MPI_Comm_group(MPI_COMM_WORLD, &orig_group);
/* Divide tasks into two distinct groups based upon rank */
if (rank < NPROCS/2) {
MPI_Group_incl(orig_group, NPROCS/2, ranks1, &new_group);
}
else {
MPI_Group_incl(orig_group, NPROCS/2, ranks2, &new_group);
}
/* Create new new communicator and then perform collective communications */
MPI_Comm_create(MPI_COMM_WORLD, new_group, &new_comm);
MPI_Allreduce(&sendbuf, &recvbuf, 1, MPI_INT, MPI_SUM, new_comm);
MPI_Group_rank (new_group, &new_rank);
printf("rank= %d newrank= %d recvbuf= %d\n",rank,new_rank,recvbuf);
MPI_Finalize();
}
mpirun -n <# of processes> ./myprog