Count and sum up duplicate records in a file (UNIX)

I'll take a few guesses here, since its not entirely clear what's needed. First I'll assume your file looks something like this:

apple
banana
pear
apple
pear
apple

I assume "Total Data Count" is simply the number of entries, i.e. the total number of lines in the file. wc -l is the tool for that:

$ echo "Total Data Count: $(wc -l < temp_file)"
Total Data Count: 6
$ 

Then "Duplicate Data Count" is one of two things:

If it is the count of all records that are duplicated (5 = "apple", "apple", "apple", "banana", "banana" in my example), uniq -dc to get counts of duplicated fields, then awk to sum them up:

$ echo "Duplicate Data Count: $(sort temp_file | uniq -dc | awk '{count+=$1} END {print count}')"
Duplicate Data Count: 5
$ 

If it is the number of records that contain duplicates (but not full count of all duplicates) (2 = "apple", "banana" in my example), then wc -l of uniq -d should be sufficient:

$ echo "Duplicate Data Count: $(sort temp_file | uniq -d | wc -l)"
Duplicate Data Count: 2
$ 

I'm assuming "Final Data Count" is the number of all records with duplicates removed (3 = "apple", "pear", "banana" in my example). Here we can just pipe plain uniq to wc -l:

$ echo "Final Data Count: $(sort temp_file | uniq | wc -l)"
Final Data Count: 3
$