Java - How to replace "java.util.InputMismatchException" error with something else

Question

How do I make it so a "java.util.InputMismatchException" doesnt show?

For example:

import java.util.Scanner;

class Test {
  public static void main(String args[]){

    Scanner input = new Scanner(System.in);
    int number;

    System.out.print("Type a number: ");
    number = input.nextInt();
    System.out.println(number);

    input.close();
  }
}

It works fine when you type in a valid int, like "5", but when the user type an invalid int, like "5.1" or "a", it will give the error Exception in thread "main" java.util.InputMismatchException. Is there a way to bypass the error and display/do something else if the user types in a non-valid int?

Like so:

Type in a number: a
That is not a valid number. Try again

See docs.oracle.com/javase/tutorial/essential/exceptions/index.html — vandale
– vandale, Commented Mar 31, 2014 at 2:04

locoyou · Accepted Answer · 2014-03-31 02:10:48Z

1

First, you can catch the exception and do something you want.

A better way is use Scanner.hasNextInt() to test whether the line user input is a int.

System.out.println("Type a number");
while(!input.hasNextInt()) {
    input.nextLine();
    System.out.println("That is not a valid number. Try again");
}
number = input.nextInt();

answered Mar 31, 2014 at 2:10

locoyou

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Comments

pushkin · Accepted Answer · 2014-03-31 02:11:10Z

0

number = input.nextInt();

The line above reads an integer. The exception means you're inputting something that is something else (e.g. String, double)

Note: if you want to read any number, replace that line with:

number = input.nextDouble();

answered Mar 31, 2014 at 2:11

pushkin

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