I’m new in PHP, and I want to do the same as the follow java source-code in PHP. Can anyone help me?
someMethod(int i) {
System.out.println("message");
// more code
}
someMethod(String s) {
System.out.println("another message");
// more different code
}
You cannot overload PHP functions, as their signatures only include their name and not their argument lists: https://stackoverflow.com/a/4697712/386869
You can either do two separate functions (which I recommend) for what you're trying to do, or perhaps write one function and perform a different action for each type.
Writing two methods is straightforward:
function myFunctionForInt($param)
{
//do stuff with int
}
function myFunctionForString($param)
{
//do stuff with string
}
If you'd like to instead do it with one function and check the type (not really recommended):
function myFunction($param)
{
if(gettype($param) == "integer")
{
//do something with integer
}
if(gettype($param) == "string")
{
//do something with string
}
}
I don't know that it's the best way. Also, for your particular example, Imat's example makes the most sense since you're just printing a message.
myFunction with a string, then differentiate the function by naming it myFunctionWithString (or something similarly distinctive).
Okay, so you want to create a function that prints a message.
function my_function_name()
{
echo "your message here;
}
If you want a function with parameters, you can do this.
function my_function_name($params)
{
echo "your message here";
echo $params; //call the paramereters
}
You cannot overload PHP functions. Function signatures are based only on their names and do not include argument liststaken from this post stackoverflow.com/questions/4697705/php-function-overloadingfunction someFunction(){}likesomeFunction($param1,$param2);. Note the parameter count is more in the calling.