Return a 302 status code in Spring MVC Controller

Question

I am developing a Spring MVC app, and I need to check in my controller a certain condition. In case it were true, I have to return a 302 status code. It's something like this:

@RequestMapping(value = "/mypath.shtml", method = RequestMethod.GET)
public ModelAndView pageHandler(@Valid MyForm form, BindingResult result, HttpServletRequest request,
        Locale locale) throws PageControllerException, InvalidPageContextException, ServiceException {

    if (someCondition){
        // return 302 status code
    }
    else{
        // Do some stuff
    }
}

Which is the best way to do this?

Thank you very much in advance

Note that a 302 is not an error, but you still might be able to use Spring's exception framework to map an exception type to 302. — chrylis -cautiouslyoptimistic-
– chrylis -cautiouslyoptimistic-, Commented Jun 3, 2014 at 11:26
Sorry about it, I have changed the "error" word for status code — Genzotto
– Genzotto, Commented Jun 3, 2014 at 11:40
I found the way to do it that works perfectly for me. I posted the answer — Genzotto
– Genzotto, Commented Jun 3, 2014 at 11:48

Community · Accepted Answer · 2017-05-23 12:02:23Z

6

I finally managed to do it using @ResponseStatus, as shown here:

https://stackoverflow.com/a/2067043/2982518

UPDATE

This is the way I finally did it:

@ResponseStatus(value = HttpStatus.MOVED_TEMPORARILY)
public class MovedTemporarilyException extends RuntimeException {

    // ...
}

@RequestMapping(value = "/mypath.shtml", method = RequestMethod.GET)
public ModelAndView pageHandler(@Valid MyForm form, BindingResult result, HttpServletRequest request,
        Locale locale) throws PageControllerException, InvalidPageContextException, ServiceException {

    if (someCondition){
        throw new MovedTemporarilyException();
    }
    else{
        // Do some stuff
    }
}

edited May 23, 2017 at 12:02

CommunityBot

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answered Jun 3, 2014 at 11:46

Genzotto

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8 Comments

geoand Over a year ago

That will change the status in all conditions. Not just for the condition you mentioned. What I mean is that even if your condition is not true, it will still return 302

Genzotto Over a year ago

@geoand I am only going to throw this exception in case my condition were true, otherwise I'll do whatever I need. I updated my answer to show you how.

geoand Over a year ago

Ok, I see what you are saying! Both solutions will work

Panthro Over a year ago

how did you setup the url to send as it's a redirect?

Genzotto Over a year ago

@Panthro I don't understand your question, could you explain it clearer?

|

geoand · Accepted Answer · 2014-06-03 11:36:02Z

3

The following code will do:

if (someCondition){
    return new ModelAndView("redirect:" + someUrl)
}
else{
        // Do some stuff
}

edited Jun 3, 2014 at 11:36

answered Jun 3, 2014 at 11:20

geoand

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1 Comment

Genzotto Over a year ago

I found the way to do it that works perfectly for me. I posted the answer

Sled · Accepted Answer · 2021-07-30 18:46:26Z

1

org.springframework.web.servlet.view.RedirectView has a few simple parameters. One of the parameters removes the model attributes from the URL.

The previous answers worked for me, but the redirect Location header was including the model attributes added by some interceptor post methods.

return new RedirectView(newLocationVia302, true, true, false);

edited Jul 30, 2021 at 18:46

Sled

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answered May 6, 2016 at 19:47

englebart

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