How to get the name of this file using formidable (NodeJs)

Question

I have a form using nodejs + express

Jade File:

form(method="post", action="/upload", enctype="multipart/form-data")
  input(type="file" name="image")
  button(type="submit") Upload

Index.js not all code just the necessary

var formidable = require('formidable'),
http = require('http'),
util = require('util');
var fs = require('fs');


MyProject.post('/upload',function(req, res){
var form = new formidable.IncomingForm();
form.parse(req, function(err, fields, files) 
{
  console.log(files);
});

When I use console.log(files) the result is this

{ iProducto:
  { domain: null,
 _events: {},
 _maxListeners: 10,
 size: 1262294,
 path: 'C:\\DOCUME~1\\ADMINI~1\\CONFIG~1\\Temp\\556696bb1c0c6a54362b746c4445
  45ca',
 name: 'Dibujo.bmp',
 type: 'image/bmp',
 hash: null,
   lastModifiedDate: Mon Jun 09 2014 21:25:42 GMT-0100 (Hora estándar de Cabo
 Verde),
 _writeStream:
  { _writableState: [Object],
    writable: true,
    domain: null,
    _events: {},
    _maxListeners: 10,
    path: 'C:\\DOCUME~1\\ADMINI~1\\CONFIG~1\\Temp\\556696bb1c0c6a54362b746c4
    44545ca',
    fd: null,
    flags: 'w',
    mode: 438,
    start: undefined,
    pos: undefined,
    bytesWritten: 1262294,
    closed: true } } }

Now it is ok but I need the file name and if I use console.log(files.name) the result is undefined how can I get the name value

mscdex · Accepted Answer · 2014-06-09 22:34:56Z

6

You can access the filename by the field name: files.iProducto.name.

answered Jun 9, 2014 at 22:34

mscdex

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1 Comment

krlosruiz Over a year ago

OHH It works! thanks I don't know why I didn't try this!

Liam Tormey · Accepted Answer · 2021-06-08 14:32:11Z

1

Not sure if the above answer is outdated, but the following gets the filename of the file being uploaded.

files.file.name

Below can be used to get the filename of the file, after being renamed by formidable:

var path = require("path");
const name = path.basename(files.file.path)

edited Jun 8, 2021 at 14:32

answered Jun 8, 2021 at 14:24

Liam Tormey

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Comments

node_saini · Accepted Answer · 2024-04-11 11:07:30Z

0

In the current latest version, you can get the file name by files.file[0].originalFilename and you can get the file path by files.file[0].filepath.

Earlier it was files.file.name and files.file.path

answered Apr 11, 2024 at 11:07

node_saini

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