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Here is my C code in an Objective-C method

char addressBuffer[100];

But how to define this char in Swift language?

I try something like this but this doesn't work:

var addressBuffer : CChar(100)

Here is the documentation https://developer.apple.com/library/prerelease/ios/documentation/swift/conceptual/buildingcocoaapps/InteractingWithCAPIs.html

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    use String instead. If you need a char[100], you should use the C language instead. I don't see a reason for Swift-Code to use a char[100] type Commented Jun 20, 2014 at 15:54
  • Recall: "Objective-C with out the C" Commented Jun 20, 2014 at 15:56
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    I use netServiceDidResolveAddress delegate and in this method I use sockets which are implemented in C language. socket->C language Commented Jun 20, 2014 at 15:56
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    @Zaph I hope Objective-C will not go away. I like it much more than Swift. Maybe I should become a Cobol programmer instead, or write Android apps... No, seriously, I don't like Swift... I like private methods, a non-managed language and I like to know how exactly my code is translated to assembler. It would be much nicer if ObjC were just extended with value types and generics. No need to create a new language. Commented Jun 20, 2014 at 16:10
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    @Michael I see I am loosing much with Swift and that there are to many optional shortcuts that are definitely affect readability. Every devs are going to come up with a bewildering variety of coding styles, a "Code of Babble". I am already seeing operator over-loadings that just shouldn't happen, the worst of C++ has arrived. Commented Jun 20, 2014 at 16:36

3 Answers 3

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12

that is the way to get a nice unicode character array in Swfit:

var charArray: Array<Character> = Array(count: 100, repeatedValue: "?")

if fills your array with 100 question marks, initially.

update

with CChar, for instance:

var charArray: Array<CChar> = Array(count: 100, repeatedValue: 32) // 32 is the ascii space
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3 Comments

Okey maybe it will be good but how to define a char array (100) with CChar type?
what's the difference between them?
@AlexanderSupertramp, the CChar is literally an alias for Int8 in Swift.
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This Swift code seems to allocate something usable as a C char array of size 100 (for C interoperation needs):

var addressBuffer = [Int8](count: 100, repeatedValue: 0)

// test it
addressBuffer[0] = 65 // 'A'
addressBuffer.withUnsafePointerToElements() { (addrBuffPtr : UnsafePointer<CChar>) -> () in
      // use pointer to memory
      var x0 = addrBuffPtr.memory
      println("The ASCII value at index 0 is \(x0)")

      var myCOpaquePointer = COpaquePointer(addrBuffPtr)
      // use C pointer for interoperation calls
}
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3 Comments

developer.apple.com/library/prerelease/ios/documentation/swift/… pls see it
Did you find some problem with the documentation?
C signed char variables (if you need them for interoperation with some existing C library using type char) aren't for use with unicode data.
6

hotpaw2's answer in Swift 4+

var addressBuffer = [Int8](repeating: 0, count: 100)
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