I have a string in this pattern:
2(some_substring) -> 3(some_other_substring)
Now these number can be anything.
I think this answer would solve the problem. But it gives all the integers in one variable. I want them to be in different variables, so that I can analyze them. Can we split it? But Splitting would cause problem:
If the the numbers are not single-digit, then the splitting will be erroneous.
Is there any other way?
You can use a variation of this: instead of removing the non-digit characters, you can extract all digit characters into a list:
set text {2(some_substring) -> 3(some_other_substring)}
set numbers [regexp -all -inline -- {[0-9]+} $text]
puts $numbers
# => 2 3
And to get each number, you can use lindex:
puts [lindex $numbers 0]
# => 2
Or in versions 8.5 and later, you can use lassign to assign them to specific variable names:
lassign $numbers first second
puts $first
# => 2
puts $second
# => 3
In regexp -all -inline -- {[0-9]+} $text, -all extract all the matches, -inline puts the matches into a list, -- ends the options, [0-9]+ matches at least one integer.
To extend Jerry's answer, in case digits can appear within the parentheses, a regular expression to only extract digits that are immediately followed by an open parenthesis is: {\d+(=\()}
% set text {2(some_6substring) -> 3(some_other_5substring)}
2(some_6substring) -> 3(some_other_5substring)
% lassign [regexp -all -inline {\d+(?=\()} $text] first second
% set first
2
% set second
3
This assumes that you don't have nested parentheses.
