Extracting number from string using regular expression

Question

After executing a command

if {[execCmd -cmd "xstatus call status" -expectingValue OK -waitTime 5]} {
puts "the Buffer value after executing the command is something like this>>>>>>>>>>>>>>>>>>$buffer<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<\n"
}

i got the output as

the Buffer value after executing the command is something like this>>>>>>>>>>>>>>>>>>): 
** end
xstatus call status
*s Call 161 Status: Connected
** end

OK<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<

Now i need the integer value to be extracted from it. How to do it ? I have tried many things but it is not working.

Dinesh · Accepted Answer · 2014-11-25 04:25:47Z

2

You can try it like

puts [regexp -inline {\d+} $buffer]

\d will match the any numerical value from 0 to 9. + will match one or more occurrence. So together, \d+ will match one or more occurrence of numerical values.

Have a look at Tcl's man page of regexp, to know more about the same.

Note : We are happy to help you out. But, always show us the code which you have tried.

edited Nov 25, 2014 at 4:25

answered Nov 24, 2014 at 6:53

Dinesh

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4 Comments

krishna chaitanya Over a year ago

so if i use puts [ regexp -inline {\d+} $buffer ]; it will search whole output or a particular line, there is no need to break the line and all

Dinesh Over a year ago

It will search in the whole output. No need to break the line.

Dinesh Over a year ago

@Hoodiecrow : Thanks Hoodiecrow. I have updated the answer and will follow those.

Peter Lewerin Over a year ago

Thanks. It's details, but they matter. Nice answer btw.

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