get the output of array in deciending order using php

Question

i have one php array
and i want to draw output of this array in something like deciding type.
Here is my php code

<?php
$data = array('A','B','C','D','E','F');
$count = count($data);
for($k = 0;$k<$count;$k++){
    foreach($data as $key => $value){
        if($key == $k){
            $datanew = $count - $k;
            for($i=0 ; $i<$datanew ; $i++){
                echo "X";
            }
        }else{
            echo "V";
        }
    }
    echo "</br>";
}
?>

current output

XXXXXXVVVVV
VXXXXXVVVV
VVXXXXVVV
VVVXXXVV
VVVVXXV
VVVVVX

excepted output

XXXXXX
VXXXXX
VVXXXX
VVVXXX
VVVVXX
VVVVVX

insort after X no V

what logic i want to implicit to get perfect output.
thanks

Yannici · Accepted Answer · 2014-07-07 09:18:18Z

2

I hope you're happy with the following solution:

<?php

$data = array('A', 'B', 'C', 'D', 'E', 'F');
$count = count($data);
for ($k = 0; $k < $count; $k++) {
    echo str_repeat("V", $k);
    echo str_repeat("X", $count-$k);
    echo "<br />";
}
?>

I used str_repeat to repeat the chars X and V. So you just need only one for-loop.

Output:

XXXXXX
VXXXXX
VVXXXX
VVVXXX
VVVVXX
VVVVVX

Example on Ideone.com

edited Jul 7, 2014 at 9:18

answered Jul 7, 2014 at 9:12

Yannici

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Comments

ALOK · Accepted Answer · 2014-07-07 09:41:29Z

0

Simple just add break in your code as below:

    <?php
     $data = array('A','B','C','D','E','F');
     $count = count($data);
     for($k = 0;$k<$count;$k++){
       foreach($data as $key => $value){
          if($key == $k){
            $datanew = $count - $k;
               for($i=0 ; $i<$datanew ; $i++){
                  echo "X";
                }
               break;
             }
          else{
            echo "V";
           }
        }
       echo "</br>";
     }
   ?>

And output as you wanted

answered Jul 7, 2014 at 9:41

ALOK

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