PHP for loop order

Question

I want to ask pretty simple question (for most of you) but I can't find the solution right now.

We have $names = array('Alex','James','Jack');

I want to use for loop to echo this:

1. Alex
2. James
3. Jack

But I'm using this loop right now which isn't working as I want it to:

for($i = 0; $i <= count($names); $i++) { echo $i.$names[$i]."<br/>"; }

and it's echoing this:

0. Alex
1. James
2. Jack

The problem is because we are starting from 0 because it's an array. If I put a starting point 1 it's missing the first object from the array.

What's the fix for that?

why not use a foreach loop? same output essentialy just imho easier when used on arrays — happymacarts
– happymacarts, Commented Jan 3, 2017 at 17:16
Echo $i + 1 instead of $i? If you want to add 1 to a value, + 1 does just that. — David
– David, Commented Jan 3, 2017 at 17:16

wogsland · Accepted Answer · 2017-01-03 17:17:40Z

3

Why not just increment your variable

$names = array('Alex','James','Jack');
for($i = 0; $i <= count($names); $i++) { 
    $j = $i+1;
    echo $j.$names[$i]."<br/>"; 
}

answered Jan 3, 2017 at 17:17

wogsland

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1 Comment

Because I'm still drunk... Thanks. :)