Shy to ask but I cannot figure out why I get only the first character from guests->name in output ? How to print the whole string ?
#include <iostream>
using namespace std;
struct name_table {
char name[20];
};
int main(){
name_table *guests = new name_table;
cout << "Please enter the the line:";
cin.get(guests->name, 20);
cout << "Okay, the line saved: " << *(guests)->name << endl;;
cin.get();
return 0;
}
Thank you
*(guests)->name
^^^^^^^^^^^^^^^
|^^^^^^^^^^^^^^
| |
| guests->name
| |
| a char[20]
| |
| becomes char*
| when passed into
| operator<<
|
\
dereference
Applying dereference to the pointer gives you a single char.
tl;dr: You are printing a single character.
You can write:
guests->name
std::cin is already clever enough to treat the char* as a C-string and iteratively print the whole string, character by character.
However, I would advise reading into a std::string; in C++ you do not need to mess around with raw character arrays. Also, you have a memory leak and that dynamic allocation is totally needless.
Here's what I'd do:
#include <iostream>
#include <string>
int main()
{
std::string name_table;
std::cout << "Please enter the the line: ";
std::getline(std::cin, name_table);
std::cout << "Okay, the line saved: " << name_table << std::endl;
}
guests is a pointer to your struct. In your output *(guests)->name, you use both the * and the -> operator, which get evaluated as follows:
(guests)->name first accesses the name member of the object behind the pointer guests. The parentheses are ignored / optional.
The so obtained char array is then dereferenced using the * operator, leading to a single char.
So what you really want is one of the following:
Either remove the *, and the parentheses can be removed: guests->name, like you did in your cin.get-line.
Or put the * in the parentheses to dereference guests and then use the . operator (instead of -> for accessing the member: (*guests).name
you have to remove * in your count line.
cout << "Okay, the line saved: " << (guests)->name << endl;
