PHP: Can't output the number 0

Question

I have an input box where a user can input a number and then that number will be outputted into an html page. It all works fine except when you enter in the number 0 it doesn't output anything but it needs to say 0. This is a live baseball game scoring plugin I wrote for WordPress so I need "Inning 1" to read "0" if no runs were scored. Here is the gist of my code:

$t1Inning1 = ( $instance['t1Inning1'] ) ? $instance['t1Inning1'] : '-';

<div><?php echo $t1Inning1 ?></div>

<label for="<?php echo $this->get_field_id('t1Inning1'); ?>">
  <input id="<?php echo $this->get_field_id('t1Inning1'); ?>" 
  name="<?php echo $this->get_field_name('t1Inning1'); ?>"
  value="<?php echo esc_attr( $instance['t1Inning1'] ); ?>"
  maxlength="2" size="3" />
</label>

You can see the output at http://juniorregionals.com/ in the middle left. The '-' is just the default value which doesn't change when you input 0 in the plugin and save it but again I need it to read 0 if you input 0.

Let me know if I need to be more specific

Try ending your <div><?php echo $t1Inning1 ; ?></div>

Nick Tucci
– Nick Tucci

2014-07-27 23:25:27 +00:00
Commented Jul 27, 2014 at 23:25 — Nick Tucci
– Nick Tucci, Commented Jul 27, 2014 at 23:25

scrowler · Accepted Answer · 2014-07-27 23:29:52Z

3

You're using the ternary operator on 0 which is a falsy value, e.g.

echo 0 ? 1 : 2; // 2

Perhaps you meant to check if $instance["t1Inning1"] is set rather than falsy?

$t1Inning1 = isset($instance['t1Inning1']) ? $instance['t1Inning1'] : '-';

edited Jul 27, 2014 at 23:29

scrowler

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answered Jul 27, 2014 at 23:28

Marty

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7 Comments

agon024 Over a year ago

That worked. It lets me put in the 0 and it displays the 0. Awesome! I still need the output to have a dash (-) as the value by default. that way the innings that have yet to be played will show a dash (-) as the score. Which is how it looks if I take out the "isset".

Marty Over a year ago

@agon024 I assume the value is always supplied then, just with some alternate value? Otherwise you would indeed see a dash.

agon024 Over a year ago

In the original code: || $t1Inning1 = ( $instance['t1Inning1'] ) ? $instance['t1Inning1'] : '-'; || this '-' gave it a default value of a dash. with the isset in there it is just blank.

agon024 Over a year ago

isnt this my correct format: $items = isset(condition) ? value_if_condition_true : value_if_condition_false;

agon024 Over a year ago

Someone has the know the answer. I am running out of time to get this working. Plzzzzz help :)

|

agon024 · Accepted Answer · 2014-07-29 13:59:38Z

0

Someone from the WordpressStackexchange site had me add an exact comparison:

$t1Inning1 = isset( $instance['t1Inning1'] ) && $instance['t1Inning1'] !== '' ? $instance['t1Inning1'] : '-';

and that works flawlessly. Thanks for all your help @Marty. You actually got the ball rolling fast.

answered Jul 29, 2014 at 13:59

agon024

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