How to declare a multi-multi- dimensional array

Question

Sounds simple and it probably is.

I have this variable:

byte[,,] data = new byte[360,288]

And I want 4 for them.

I do not want this though:

byte[,,,] data = new byte[360,288,4]

I prefer this:

byte[,,][] data = new byte[360,288][4]

Is it possible?

@Damian Thanks for the link but it does not solve my question unfortunately. — Andrew Simpson
– Andrew Simpson, Commented Aug 2, 2014 at 18:43
Look at my answer I think it is what you need, I inverted the dimensions but you could do it with a nested for if you want to keep the dimensions you have shown in your example. — BlueTrin
– BlueTrin, Commented Aug 2, 2014 at 18:47

BlueTrin · Accepted Answer · 2014-08-02 18:46:34Z

2

Yes this is a special case of jagged arrays, one where one of the jagged dimension is multidimensional.

You should write something like this:

        // Initialise 4 arrays of two dimensional arrays
        byte[][,] data = new byte[4][,];
        // Initialise the arrays
        for (var i = data.GetLowerBound(0); i <= data.GetLowerBound(0); ++i)
            data[i] = new byte[360, 258];

Of course you can invert the dimensions if you need it.

        // Initialise 4 arrays of two dimensional arrays
        byte[,][] data2 = new byte[360,258][];
        // Initialise the arrays
        for (var i = data2.GetLowerBound(0); i <= data2.GetLowerBound(0); ++i)
            for (var j = data2.GetLowerBound(1); j <= data2.GetLowerBound(1); ++j)
                data2[i,j] = new byte[4];

answered Aug 2, 2014 at 18:46

BlueTrin

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Andrew Simpson Over a year ago

Hi, yes I did a Google search and implemented it. It matches your answer so thanks!

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