I'm learning about multidimensional array in C programming. But the printf function is not working. Here is my code:
#include <stdio.h>
int main (void)
{
int array[2][3][4];
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 4; j++)
{
for (int k = 0; k < 5; k++)
{
array[i][j][k] = k;
printf("array[%d][%d][%d] = %d\n", i, j, k, array[i][j][k]);
};
};
};
printf("Loop is finished!");
return 0;
}
You are going to loop out of bounds.
Take the first dimension, 2, your loop is < 3.... so its going to use indexes 0 1 2. only 0 and 1 are valid. change your loops to i < 2, j < 3 and k < 4 respectively.
This program will not give result since it having lots of Syntax errors. you need not to be give ;- semicolon after for loop
syntax for For Loop is:
FOR( initialization expression;condition expression;update expression)
{
\\Loop content comes here
}
And also C will not permit Instant Declaration, variables should be declare @ the declaration section.
Your Program can be improved by applying these changes, then it gives output. the code snippet will be like the following:
#include <stdio.h>
int main ()
{
int array[3][4][5];
int i,j,k;
for ( i = 0; i < 3; i++)
{
for ( j = 0; j < 4; j++)
{
for (k = 0; k < 5; k++)
{
array[i][j][k] = k;
printf("array[%d][%d][%d] = %d\n", i, j, k, array[i][j][k]);
}
}
}
printf("Loop is finished!");
return 0;
}
int[2]means you have 2 elements, i.e. you can access indices 0 and 1, but you're accessing 2.