preg_replace syntax (img src) and keeping part of the URL

Question

I am trying to do something similar to preg_replace syntax (img src) but I don't want to take away everything in the SRC attribute.

src="http://www.bob.com/co/02/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg"

I just want to replace the http://www0.bob.com/co/02/. It can vary.

So what I am trying to do is to replace what is between src=" to /wp-content/ in a image tag.

How can I go about this?

Here is the code I tried:

$content = preg_replace('!(?<=src\=\").+(?=\"(\s|\/\>))!', 'http://alex.com/wp-content/', $content);

Erlesand · Accepted Answer · 2014-08-14 16:01:06Z

You can use,

$str = 'src="http://www.bob.com/co/02/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg"'; 

preg_replace("/(src=\")(.*)(\/wp-content)/", "$1http://example.com$3", $str);

Which would return,

src="http://example.com/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg"

Greedy / Non-greedy

The comment about non-greedy means that instead of using (.*) you could use (.*?). The reason you would make it non-greedy is due to the fact that (.*) would match as much as it possibly can, for example if your string contained two image links:

$str = '<img src="http://www.bob.com/co/02/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg" /> <img src="http://www.bob.com/co/02/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg" />';

Then (.*)in the regex would match everything from the first "http://..." all the way until the second "/wp-content",

print_r(preg_replace("/(src=\")(.*)(\/wp-content)/", "$1http://example.com$3", $str));
                                ^^

This would then return <img src="http://example.com/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg" />

Using a non-greedy catch instead would yield this result,

print_r(preg_replace("/(src=\")(.*?)(\/wp-content)/", "$1http://example.com$3", $str));
                                ^^^ 
<img src="http://example.com/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg" /> <img src="http://example.com/wp-content/uploads/2014/07/david_hasselhoff_at_the_dome_5.jpg" />

Federico Piazza · Accepted Answer · 2014-08-13 15:15:32Z

1

You can use this regex to get the content until wp-content:

src="(.*)\/wp-content

Working demo

enter image description here

Match information

MATCH 1
1.  [5-29]  `http://www.bob.com/co/02`
MATCH 2
1.  [98-113]    `http://alex.com`

answered Aug 13, 2014 at 15:15

Federico Piazza

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1 Comment

Federico Piazza Over a year ago

@M42 thanks for the suggestion but saw that OP already marked the question as solved.

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