remove img tag src is a url using preg_replace

Question

Hi I would like to remove a img tag with it's src is a url in a content using preg_replace

ex.

    $content = "<center><img src="http://example.net/wp-content/uploads/2012/10/cell-degeneration-contn.jpg" alt="" title="cell-degeneration-contn" width="950" height="272" class="alignnone size-full wp-image-100" /></center><h2>A first-in-class approach to stop & reverse </h2>";

so output would be:

    $content="<center></center><h2>A first-in-class approach to stop & reverse </h2>";

but best output would be if possible is :

    $content="A first-in-class approach to stop & reverse ";

welcome to stack overflow. As Marc B pointed it seems that regex is not the way to operate html text; just clarify if you really to use need preg_replace — quinestor
– quinestor, Commented Nov 2, 2012 at 17:49

Samuel Cook · Accepted Answer · 2012-11-02 19:37:28Z

2

preg_match_all() would work here, but with HTML it's not the most efficient.

$content = '<center><img src="http://example.net/wp-content/uploads/2012/10/cell-degeneration-contn.jpg" alt="" title="cell-degeneration-contn" width="950" height="272" class="alignnone size-full wp-image-100" /></center><h2>A first-in-class approach to stop & reverse </h2>';

preg_match("/<h2>(.*)<\/h2>/",$content,$matches);
$output = $matches[1];
echo $output;

The easiest way is to just use strip_tags()

$output = strip_tags($content);
echo $output;

edited Nov 2, 2012 at 19:37

answered Nov 2, 2012 at 17:30

Samuel Cook

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1 Comment

Shahrokhian Over a year ago

why preg_match_all and not preg_match ? :-??

otporan · Accepted Answer · 2012-11-02 17:39:09Z

1

You can do that this way:

    $content = "<center><img src='http://example.net/wp-content/uploads/2012/10/cell-degeneration-contn.jpg' alt='' title='cell-degeneration-contn' width='950' height='272' class='alignnone size-full wp-image-100' /></center><h2>A first-in-class approach to stop & reverse </h2>'";
    preg_match("/<h2>(.+)<\/h2>/", $content, $matches);  
    $match = $matches[1];
    echo $match;

answered Nov 2, 2012 at 17:39

otporan

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