Can't use URL module on Node.js, cannot call method 'parse' of undefined

Question

I'm trying to get parameters from a URL, for example:

http://localhost:8888/?name=test

To get name parameter I saw some samples where they use the url module like this:

var url = require('url');

var urlParts = url.parse(request.url, true);
var query = urlParts.query;

So, first I ran this command npm install url, also the dependency is on the package.json file, but I always get this error:

TypeError: Cannot call method 'parse' of undefined
at C:\Users\Administrator\git\test\app.js:28:7

Anyone has faced this problem before?

I found the problem (see comment below), thanks for your time :) — CIOC
– CIOC, Commented Aug 20, 2014 at 21:02

CIOC · Accepted Answer · 2014-08-20 21:02:17Z

12

I found the problem, I had the code like this:

var http = require("http");
var url = require('url');

http.createServer(function(request, response) {
    var urlParts = url.parse(request.url, true);
    var query = urlParts.query;
}).listen(appport);

And the url object was not accessible inside the createServer function (not sure why), so I just replace this line:

var urlParts = url.parse(request.url, true);

with this:

var url_urlParts = require('url').parse(request.url, true);

and now is working fine.

answered Aug 20, 2014 at 21:02

CIOC

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3 Comments

loganfsmyth Over a year ago

Did you perhaps have a second var url inside the createServer callback somewhere?

John Teague Over a year ago

My only concern with your solution is that require is one of few synchronous methods in node (it was a nightmare when it wasn't apparently) so you're making a blocking call in handler. This may or may not be an issue, because it's also pretty smart and caches requested files. Just might want to verify that.

CIOC Over a year ago

Thanks John, I didn't know about that, I'm going to take a closer look at this

pbatey · Accepted Answer · 2017-06-02 14:56:20Z

2

This one bit me too - my problem was that url.parse was conflicting with a local var url. I solved it like this:

import { parse as urlparse } from 'url'
var url = 'https://localhost:80'
var parsed_url = urlparse(url)

Thanks @loganfsmyth for the insight!

edited Jun 2, 2017 at 14:56

answered Jun 1, 2017 at 23:27

pbatey

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Comments

Panos Kontogiannis · Accepted Answer · 2021-05-04 12:54:20Z

-1

function parse(urlStr: string, parseQueryString: true, slashesDenoteHost?: boolean): UrlWithParsedQuery (+3 overloads) @deprecated — since v11.0.0 - Use the WHATWG URL API.

'(urlStr: string, parseQueryString: true, slashesDenoteHost?: boolean): UrlWithParsedQuery' is deprecated.ts(6385) url.d.ts(51, 9): The declaration was marked as deprecated here.

edited May 4, 2021 at 12:54

answered May 4, 2021 at 12:40

Panos Kontogiannis

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1 Comment

Panos Kontogiannis Over a year ago

DEP0116: Legacy URL API# History Version Changes v15.13.0 Deprecation revoked. Status changed to "Legacy". v11.0.0 Documentation-only deprecation. Type: Deprecation revoked The Legacy URL API is deprecated. This includes url.format(), url.parse(), url.resolve(), and the legacy urlObject. Please use the WHATWG URL API instead.

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