Matching Numbers after string

Question

I have a very simple string I am trying to match but can't seem to get it working. I want to match some numbers after a string and also emit the trailing %.

encodeTime=10%

I have tried look ahead but it doesn't seem to work. It just matches the entire string.

(?=encodeTime=)[^\s]+

Is there a way I can just match the numbers only and also emit the % after?

You couldn't find a regex that just matches a series of numeric digits? Did you look? — Servy
– Servy, Commented Aug 28, 2014 at 17:30

Avinash Raj · Accepted Answer · 2014-08-28 17:29:27Z

1

You need a lookbehind for this purpose and this (?=encodeTime=) is not a valid positive lookbehind.

(?<=encodeTime=)\d+

DEMO

answered Aug 28, 2014 at 17:29

Avinash Raj

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hwnd · Accepted Answer · 2014-08-28 18:01:03Z

1

You don't need any kind of lookaround assertion for something as simple as this. Use a capturing group and use the Match.Groups Property to reference the group and print your match result.

String s = "encodeTime=10%";
Match m  = Regex.Match(s, @"encodeTime=(\d+)");
if (m.Success)
   Console.WriteLine(m.Groups[1].Value); //=> "10"

answered Aug 28, 2014 at 18:01

hwnd

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