Remove characters from string regex java

Question

Hello guys I'm starting to learn regex and I want to replace some characters from string.

this is my test case:

Example string:

+52 924 340 2304

Expected output:

09243402304

This is what I've tried:

String number = cursor.getString(col_number).replace("\\d{2}", "");

But I can't seem to get my expected output. Any help? I would gladly appreciate your help. Thanks.

Update:

Also, I want to remove all whitespace characters from the string and I forgot to add if the string has other characters like (,),-

Don't use regex for this, you can simply cut the number using substring. — Maroun
– Maroun, Commented Sep 8, 2014 at 8:41

aelor · Accepted Answer · 2014-09-08 08:45:48Z

1

use this :

.replaceAll("^[^\\s]+|\\s", "")

demo here : http://regex101.com/r/uY9xB2/1

answered Sep 8, 2014 at 8:45

aelor

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2 Comments

Cedy Lee Over a year ago

thanks it works! But I have to change to: replaceAll("^[^\\s]+|\\s", "")

Avinash Raj Over a year ago

instead of negated character class, you could use ^\\S+

anubhava · Accepted Answer · 2014-09-08 08:56:13Z

1

Your method:

.replace("\\d{2}", "");

will fail to work because in Java String#replace doesn't take a regex. Try String#replaceAll OR String#replaceFirst

You can use:

String number = cursor.getString(col_number).replace(" ", "").replaceFirst("\\+\\d{2}", "0");

edited Sep 8, 2014 at 8:56

answered Sep 8, 2014 at 8:41

anubhava

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1 Comment

Cedy Lee Over a year ago

I'm only getting 0. not my expected result.

Guillaume · Accepted Answer · 2014-09-08 08:58:47Z

1

String number = cursor.getString(col_number).replaceAll("^\\+\\d{2}", "0").replaceAll("[^\\d]", "")

edited Sep 8, 2014 at 8:58

answered Sep 8, 2014 at 8:51

Guillaume

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1 Comment

Guillaume Over a year ago

@Cedy Lee, I suppose you want to remove everything that's not a digit? There's a way for that, see my updated answer

PKlumpp · Accepted Answer · 2014-09-08 08:42:42Z

0

Why do you not split the String at the whitespaces. Then you replace the first entry with a 0, and concatenate the array parts to one String again. Done.

answered Sep 8, 2014 at 8:42

PKlumpp

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Comments

Maroun · Accepted Answer · 2014-09-08 08:44:24Z

0

@anibhava already mentioned your problem, I want to suggest another solution, you can simply remove the white spaces and cut the string using String#substring:

number.replaceAll("\\s+", "").substring(3); //you might want to add the 0 using + operator

answered Sep 8, 2014 at 8:44

Maroun

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Comments

vks · Accepted Answer · 2014-09-08 09:01:50Z

0

^\+\d{2}[^\d]*(\d+)[^\d]*(\d+)[^\d]*(\d+)$

You can use this and then replace with

 0$1$2$3

See demo.

http://regex101.com/r/iX5xR2/12

This will work for all cases

answered Sep 8, 2014 at 9:01

vks

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