Remove unwanted characters from string by regex in Java

Question

I have a string here:

javax.swing.JLabel[,380,30,150x25,alignmentX=0.0,alignmentY=0.0]: Hello

I want to remove everything before the ":", including the ":" itself. This would leave only "Hello". I read about regex, but no combination I tried worked. Can someone tell me how to do it. Thanks in advance!

Avinash Raj · Accepted Answer · 2015-07-12 04:02:00Z

3

You need to use replaceAll method or replaceFirst.

string.replaceFirst(".*:\\s*", "");

or

string.replaceAll(".*:\\s*", "");

This would give you only Hello. If you remove \\s* pattern,then it would give you <space>Hello string.

.* Matches any character zero or more times, greedily.
: Upto the colon.
\\s* Matches zero or more space characters.

answered Jul 12, 2015 at 4:02

Avinash Raj

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mushfek0001 · Accepted Answer · 2015-07-12 04:17:56Z

1

You could also just split the string by : and take the second string. Like this

String sample = "javax.swing.JLabel[,380,30,150x25,alignmentX=0.0,alignmentY=0.0]: Hello";

System.out.println(sample.split(":", -1)[1]);

This will output

<space>Hello

If you want to get rid of that leading space just trim it off like

System.out.println(sample.split(":", -1)[1].trim());

answered Jul 12, 2015 at 4:17

mushfek0001

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