Python regexp find non-repeated statement in source code

Question

Suppose I have source code like the following, which by assumption is perfectly syntactically valid:

MyType basket("woven"); // initialize statement

double x = 0; // miscellaneous code

MyType bucket("plastic") ; // another initialize statement

for(int i=0; i<324; ++i ) { cout << i << "\n"; }

/* example of a disposal statement */
MyType basket();

What I want to do is detect the statement MyType bucket("plastic"); because there is no subsequent corresponding MyType bucket(); statement.

Using Python, I constructed the following regular expression (using both the DOTALL and MULTILINE options). But there's a problem, and I don't know what it is.

(?P<stmt>MyType\s+[a-zA-Z0-9_]+)\(\s*"|'[^"']+"|'\s*\)\s*;[^(?P=stmt)]*$

Essentially, I need to know how to use a named group (like (?P=stmt>)) and check for repeats of it.

friedi · Accepted Answer · 2014-09-24 16:11:04Z

2

Use this one:

(MyType\s+(\S+)\([^)]+\)\s*;)(?!.*MyType\s+\2\(\s*\)\s*;)

Here is the demo

edited Sep 24, 2014 at 16:11

answered Sep 24, 2014 at 15:18

friedi

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vks · Accepted Answer · 2014-09-24 15:38:21Z

2

MyType\s*(\w+)\S+\s*;(?!.*?MyType\s*\1)

Try this.See demo.

http://regex101.com/r/zR2tR4/20

answered Sep 24, 2014 at 15:38

vks

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