The error that I am getting
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 610
at Fib.sorted(Fib.java:67)
at Fib.main(Fib.java:17)
My code
public class Fib
{
public static void main(String args[])
{
System.out.println(Arrays.toString( fiblist) );
System.out.println(Fib.add());
System.out.println(Fib.square());
System.out.println(Fib.reversal());
System.out.println(Fib.sorted());
}
public static int fiblist[] = {1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765};
public static int fiblen = fiblist.length;
public Fib()
{
// Do nothing
}
public static ArrayList<Integer> sorted()
{
ArrayList sorted = new ArrayList();
for(int counter = 0; counter < fiblist[4]; counter++ )
{
int temp1 = fiblist[counter];
System.out.println("Elements stored " + temp1);
}
for(int counter = fiblist[14]; counter < fiblist[19]; counter++)
{
int temp2 = fiblist[counter];
System.out.println("Last Elements stored " + temp2);
}
return sorted;
}
}
I'm trying to store the last 5 elements of my array in temp 2. Then I will switch them. Is there an easier way to do this? Switch the first five elements of an array with the last five? How would you switch them with a for loop?
countershould be the position in the array and not the value of that position. Changecounter < fiblist[4]tocounter < 4and changeint counter = fiblist[14]toint counter = 14to fix the problem.int counter = fiblist[14]; counter < fiblist[19];since you are getting values way higher than your list sizecounter < fiblist[19]tocounter < 19.