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The error that I am getting

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 610
at Fib.sorted(Fib.java:67)
at Fib.main(Fib.java:17)

My code

public class Fib
{
    public static void main(String args[]) 
    {
        System.out.println(Arrays.toString( fiblist) );
        System.out.println(Fib.add());
        System.out.println(Fib.square());
        System.out.println(Fib.reversal());
        System.out.println(Fib.sorted());
    }

     public static int fiblist[] = {1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765};
     public static int fiblen = fiblist.length;

     public Fib() 
     {
        // Do nothing
     }

     public static ArrayList<Integer> sorted()
     {
         ArrayList sorted = new ArrayList();

         for(int counter = 0; counter < fiblist[4]; counter++ )
         {
             int temp1 = fiblist[counter];
             System.out.println("Elements stored " + temp1);
         }
         for(int counter = fiblist[14]; counter < fiblist[19]; counter++)
         {
             int temp2 = fiblist[counter];
             System.out.println("Last Elements stored " + temp2);
         }
         return sorted;
    }
}

I'm trying to store the last 5 elements of my array in temp 2. Then I will switch them. Is there an easier way to do this? Switch the first five elements of an array with the last five? How would you switch them with a for loop?

3
  • 1
    Your counter should be the position in the array and not the value of that position. Change counter < fiblist[4] to counter < 4 and change int counter = fiblist[14] to int counter = 14 to fix the problem. Commented Oct 1, 2014 at 19:39
  • This looks like trouble int counter = fiblist[14]; counter < fiblist[19]; since you are getting values way higher than your list size Commented Oct 1, 2014 at 19:39
  • And also counter < fiblist[19] to counter < 19. Commented Oct 1, 2014 at 19:40

3 Answers 3

2

You are confusing array index and value. fiblist[19] is 6765. You want your counters to go from 0 to 4 and 14 to 19, not fiblist[19].

for(int counter = 0; counter < 4; counter++ )
{
    int temp1 = fiblist[counter];
    System.out.println("Elements stored " + temp1);
}

for(int counter = 14; counter < 19; counter++)
{
    int temp2 = fiblist[counter];
    System.out.println("Last Elements stored " + temp2);
}
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3 Comments

Don't just copy and paste the OP's formatting and correct the problem with the code, fix the formatting so people don't have to edit both the question and your answer.
This part runs. but how do I move temp1 to the end of an array? Or temp2 to the beginning of the array?
@vDc put fiblist[19] in a variable, set fiblist[19] = fiblist[0], then put the value of your variable in fiblist[0].
1

This works

for(int i=0;i<fiblist.length;i++){
   System.out.print(fiblist[i]+",");
}
System.out.println();

for (int i=0;i<5;i++){
    temp=fiblist[i];
    fiblist[i]=fiblist[fiblist.length-i-1];
    //the first ellement= the last
    //the second=second from last...
    fiblist[fiblist.length-1-i]=temp;
}

for(int i=0;i<fiblist.length;i++){
    System.out.print(fiblist[i]+",");
}

Output:

1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,
6765,4181,2584,1597,987,8,13,21,34,55,89,144,233,377,610,5,3,2,1,1,

1 Comment

would temp just display the 'movement'?
0

Try this. It's a sorting algorithm (A fairly poor one though)

public static void sort(int[] a) {
    int iMin;
    int n = a.length;
    for (int j = 0; j < n-1; j++) {
        iMin = j;
        for (int i = j+1; i < n; i++) {
            if (a[i] < a[iMin]) {
                iMin = i;
            }
        }
        if(iMin != j) {
            swap(j, iMin, a);
        }
    }
}

public static void swap(int i, int j, int[] arr){
    int temp = arr[i];
    arr[i] = arr[j];
    arr[j] = temp;
}

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