1

I'm trying to make a very, very simple query of a small mysql database, using the following code (with appropriate values in $host, etc.):

$result = mysqli_query($connection, "select university from universities_alpha");
$row = mysqli_fetch_array($result);

echo print_r($result);
echo '<br><br>';
echo print_r($row);

As you can see, I printed out the results in a human-readable way, yielding:

mysqli_result Object ( [current_field] => 0 [field_count] => 1 [lengths] => Array ( [0] => 19 ) [num_rows] => 9 [type] => 0 ) 1

Array ( [0] => Arizona State Univ. [university] => Arizona State Univ. ) 1

There are a few example universities in that column, so I'm not sure what I'm doing wrong.

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  • read the manual for the mysqli functions. you put the fetch_array in a while loop, because it returns the rows one by one until it returns null and the loop terminates. Commented Oct 16, 2014 at 23:34

2 Answers 2

7

mysqli_fetch_array works by pointers each time it's called

Imagine the following

$result = mysqli_query($connection, "select university from universities_alpha");
$row = mysqli_fetch_array($result); // this is the first row
$row = mysqli_fetch_array($result); // now it's the second row
$row = mysqli_fetch_array($result); // third row

To actually display the data the way you want it to, I suggest you do the following

$rows = array();
$result = mysqli_query($connection, "select university from universities_alpha");
while($row = mysqli_fetch_array($result)) {
    $rows[] = $row;
}

print_r($rows);
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Comments

2

If you want to fetch all rows from the result set then you must use mysqli_fetch_all() instead of mysqli_fetch_array().

Replace your code with this:

$result = mysqli_query($connection, "select university from universities_alpha");
$rows = mysqli_fetch_all($result, MYSQLI_BOTH);

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