I can't see the answer for this anywhere but I know it's a stupid question so sorry in advance!!
I have a list like this:
fullList = [("a","/a/"),("b","/b/"),("c","/c/"),("d","/d/"),("e","/e/")]
If I have the value, lets say c then how do I get it's index for the array?
If I use the index method it's doesn't work:
listIndex = fullList.index('c')
Any ideas?
Cheers and sorry if a really stupid question...
you just need a list comprehension and use in operation :
>>> [fullList.index(i) for i in fullList if 'c' in i]
[2]
If you just want to check for first index you can use this:
>>> [fullList.index(i) for i in fullList if i[0]=='c']
[2]
Also note that you can use enumerate function in your list comprehension that have more performance here , (the order of index() is O(n)) you can refuse from an extra searching !
>>> [i for i,j in enumerate(fullList) if j[0]=='c']
[2]
>>> [i for i,j in enumerate(fullList) if 'c' in j]
[2]
A list's index() looks for equality on the elements of the list, so you want to provide the item that equals what you're looking for. Specifically, in this case, it would be:
listIndex = fullList.index(('c', '/c/'))
If you really need to search by the first element of the tuple, you can grab just the first one of each item and do .index on that:
listIndex = [ e[0] for e in fullList ].index('c')
Do you need the index or the full value ? In the second case:
>>> found = dict(fullList).get('c')
>>> print found
("c", "/c/")
