How to create and fill 2d list in python. Basically trying to create a list of rgb values

Question

What I'm trying to do is allow the user to enter in the red, green, blue of there color and how many tints they want and saving that into a 2d list. Right now I am just trying to put their rgb value in the list the same number of times they enter for the tint.

So for example they enter r = 255 g = 0 b = 0 numTint = 5

I want to fill the list so it is like this for now: tintList = [(255,0,0), (255,0,0), (255,0,0), (255,0,0), (255,0,0)]

The problem is I'm am new to programming an python so I'm am not quite sure how to do this. I believe you have to use nested loops, but I am not sure how. I would really appreciate any help I can get.

def createColorList(r,g,b, numTint):
    tintList = []
    #fill tintList

    return tintList

tintList = [(r,g,b)]*numTint

ssm
– ssm

2014-11-03 01:03:19 +00:00
Commented Nov 3, 2014 at 1:03 — ssm
– ssm, Commented Nov 3, 2014 at 1:03

Gimo · Accepted Answer · 2014-11-03 03:23:34Z

1

def createColorList(r,g,b, numTint):
    tintList = []
    for x in range(0, numTint):
        tintList.append((r,g,b))
    return tintList

But I think Use a class to represent RGB value, maybe a better practice.

class Color(object):
    def __init__(self, red, green, blue, tint):
        self.red = red
        self.green = green
        self.blue = blue
        self.tint = tint

    def somemethod(self):
        pass #you can add some method.

answered Nov 3, 2014 at 3:23

Gimo

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Comments

Padraic Cunningham · Accepted Answer · 2014-11-03 01:09:19Z

0

Just use a list comprehension and range:

return [(r,g,b) for _ in range(numTint)]


In [25]: createColorList(255,0,0,5)
Out[25]: [(255, 0, 0), (255, 0, 0), (255, 0, 0), (255, 0, 0), (255, 0, 0)]

edited Nov 3, 2014 at 1:09

answered Nov 3, 2014 at 1:04

Padraic Cunningham

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