Change a query string in Django?

Question

I have requested the page:

example.com/stuff?&type=2&foo=bar&stage=unpublished

I want a link to the page (unset type and foo relative to previous):

example.com/stuff?stage=unpublished

And I want to do it conveniently like:

<a href=?{% url_params_now with foo=None type=None %}">go up</a>

How do I do it? Is there some inbuilt way, or some library?

I use the tedious

{{url}}?{% if type %}type={{type}}{% endif %}&{% if foo %}foo={{foo}}{% endif %}&{% if stage %}stage={{stage}}{% endif %}

{% url %} with params doesn't help? docs.djangoproject.com/en/dev/ref/templates/builtins/#url — dfranca
– dfranca, Commented Nov 5, 2014 at 14:52
how about just ?stage=unpublished ? You dont need to explicitly set. Also, the best bet is to handle this in the view because nothing stops the user from sending arbitrary GET parameters as a part of the request. — karthikr
– karthikr, Commented Nov 5, 2014 at 14:59
Did you take a look to Django custom tags? docs.djangoproject.com/en/dev/howto/custom-template-tags — David Dahan
– David Dahan, Commented Nov 5, 2014 at 15:00

Jesvin Jose · Accepted Answer · 2014-11-05 15:35:45Z

1

As David said, I created my own template tag. I can call stuff like {% urlgen a=1 b=2 %}. its terser and neater.

@register.simple_tag(name = 'urlgen')
def urlgen(**kwargs):
    with_present_values = dict( [ (k,v) for k, v in kwargs.items() if v])
    return query_string_from_dict( with_present_values)

and

from django.http import QueryDict
def query_string_from_dict( dic):
    query_dictionary = QueryDict('', mutable=True)
    query_dictionary.update( dic)
    if dic:
        return '?' + query_dictionary.urlencode()
    else:
        return ''

Not covered here: registering template tags with Django.

answered Nov 5, 2014 at 15:35

Jesvin Jose

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David Dahan Over a year ago

Good choice :) Cleaner than if/endif.. tags

Alex Parakhnevich · Accepted Answer · 2014-11-05 15:21:00Z

0

Consider this approach:

{{url}}?type={{type|default:""}}&foo={{foo|default:""}}&stage={{stage|default:""}}

https://docs.djangoproject.com/en/dev/ref/templates/builtins/#default

Also there is a built in default_if_none filter.

answered Nov 5, 2014 at 15:21

Alex Parakhnevich

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