count of the array gives wrong value

Question

I'm new to php and its developing . I declared php array:

<?php

     $chk_group[] =array(
         '1' => 'red',
         '2' => 'thi',
         '3' => 'aaa',
         '4' => 'bbb',
         '5' => 'ccc'      
     );

     var_dump($chk_group);

     //continue for loop
     for ($i = 0 ; $i < count($chk_group); $i++) {
         echo count($chk_group);
     }

 ?>

here i'm getting count = 1 please help me to get count of array.

In using $chk_group[] = array(...) rather than $chk_group = array(...), you've made $chk_group a multi-dimensional array, with a single entry at the top level — Mark Baker
– Mark Baker, Commented Dec 20, 2014 at 15:06

semirturgay · Accepted Answer · 2014-12-20 15:10:53Z

3

You have created a multi dimentional array by your this assigment

$chk_group[] = array(
         '1' => 'red',
         '2' => 'thi',
         '3' => 'aaa',
         '4' => 'bbb',
         '5' => 'ccc' 
     );

can you try without the brackets as :

$chk_group = array(
         '1' => 'red',
         '2' => 'thi',
         '3' => 'aaa',
         '4' => 'bbb',
         '5' => 'ccc' 
      );

edited Dec 20, 2014 at 15:10

answered Dec 20, 2014 at 15:05

semirturgay

4,1993 gold badges32 silver badges50 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Casey Rule · Accepted Answer · 2014-12-20 15:05:59Z

2

You need to change $chk_group[] to $chk_group in your first line.

In PHP syntax, $chk_group[] = means push the right had value to an array called $chk_group. Your entire array is being stored to $chk_group[0]

What you need instead is:

 $chk_group[] =array(
     '1' => 'red',
     '2' => 'thi',
     '3' => 'aaa',
     '4' => 'bbb',
     '5' => 'ccc' 
 );

answered Dec 20, 2014 at 15:05

Casey Rule

2,0952 gold badges21 silver badges28 bronze badges

Comments

esdebon · Accepted Answer · 2014-12-20 15:09:15Z

2

try

count($chk_group[0]);

or

$chk_group =array('1' => 'red',
                           '2' => 'thi',
         '3' => 'aaa',
         '4' => 'bbb',
         '5' => 'ccc' 



     );

 count($chk_group);

answered Dec 20, 2014 at 15:09

esdebon

2,7815 gold badges27 silver badges34 bronze badges

Comments

Masious · Accepted Answer · 2014-12-20 15:15:42Z

1

As mentioned in the answers, you need to remove the extra [] sign, so that assignment in front of the = sign, is recognized as the variable. With this syntax, you say that first element of your array, is another array.

answered Dec 20, 2014 at 15:15

Masious

4305 silver badges15 bronze badges

Collectives™ on Stack Overflow

count of the array gives wrong value

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related