Android - Achieving line break in XML string with String.format()?

Question

This is my xml string...

<string name="my_string">First line.\nSecond line: %1$s.\nThird line.</string>

...which I need to run through String.format without losing the line breaks.

How do I achieve that?

Here is my Java code...

String text = String.format(getString(R.string.my_string, "some text");
Spanned html = Html.fromHtml(text, this, null);
textView.setText(html);

In the xml file, I have tried using \n and   and actual new lines, but none of them produce line breaks in the textView on the UI.

What's wrong with \n? It's perfect working in my case. I used this string First line. \n Second line: %1$s.\n Third line. — M D
– M D, Commented Dec 30, 2014 at 12:30
If you wan to load string as Html then you have to use instead \n and replace '<' with '<' in like : . — Hareshkumar Chhelana
– Hareshkumar Chhelana, Commented Dec 30, 2014 at 12:40
\n worked for me when I used it with String.format(String1, String2) — Shirish Herwade
– Shirish Herwade, Commented Feb 5, 2019 at 12:07

WISHY · Accepted Answer · 2014-12-30 12:36:52Z

2

Try this for HTML string:

<?xml version="1.0" encoding="utf-8"?>
<resources>
<string name="title">Hello&lt;br /&gt;World!</string>
</resources>

answered Dec 30, 2014 at 12:29

WISHY

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1 Comment

Not required > for ending HTML-escaped string only need <.

Mister_Alan · Accepted Answer · 2014-12-30 12:33:45Z

0

For using  , as its a html tag you must wrap the string in CDATA. Use this.

<string name="my_string"><![CDATA][First line. <br />Second line. <br />Third line.]]</string>

answered Dec 30, 2014 at 12:33

Mister_Alan

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Hareshkumar Chhelana · Accepted Answer · 2014-12-30 12:43:43Z

0

Try to replace '<' with &lt; in HTML-escaped string :

<string name="my_string">First line.&lt;br/>Second line: %1$s.&lt;br/>Third line.</string>

answered Dec 30, 2014 at 12:43

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